Stange als einseitiger Hebel
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
Need help? Yes, please!
The following quantities appear in the problem:
Drehmoment \(\vec M\) /
The following formulas must be used to solve the exercise:
\(\sum \stackrel{\curvearrowleft}{M} \stackrel{!}{=} \sum \stackrel{\curvearrowright}{M} \quad \)
No explanation / solution video for this exercise has yet been created.
But there is a video to a similar exercise:
In case your browser prevents YouTube embedding: https://youtu.be/tLz4mu-j060
But there is a video to a similar exercise:
Exercise:
Am einen Ende einer drehbar gelagerten Stange g der Länge .dm sei ein Gewicht von .kg befestigt. cm von diesem Ende entfernt greife an der Stange ausserdem eine Kraft von N an. Berechne wie weit sich der Drehpunkt vom anderen Ende entfernt befindet siehe Skizze. center tikzpicture filldrawcolorblack fillblack!!white rectangle .; filldrawcolorblack .. circle .cm; drawsnakebrace .-.---.; node at .-. ?; draw ---.; drawthick colorblack .-. rectangle .-.; drawthick- latex --.; tikzpicture center
Solution:
stackrelcurvearrowleftM stackrelcurvearrowrightM M_uparrow M_S + M_G F_uparrow ell_uparrow F_S ell_S + F_G ell_G F_uparrow ell'-x F_S leftfracell-xright + F_G ell-x F_uparrow ell'-F_uparrow x F_S fracell -F_S x + F_G ell-F_G x F_S x+F_G x-F_uparrow x F_S fracell + F_G ell-F_uparrow ell' F_S+F_G-F_uparrow x F_S fracell + F_G ell-F_uparrow ell' x fracF_S fracell + F_G ell-F_uparrow ell'F_S+F_G-F_uparrow .m
Am einen Ende einer drehbar gelagerten Stange g der Länge .dm sei ein Gewicht von .kg befestigt. cm von diesem Ende entfernt greife an der Stange ausserdem eine Kraft von N an. Berechne wie weit sich der Drehpunkt vom anderen Ende entfernt befindet siehe Skizze. center tikzpicture filldrawcolorblack fillblack!!white rectangle .; filldrawcolorblack .. circle .cm; drawsnakebrace .-.---.; node at .-. ?; draw ---.; drawthick colorblack .-. rectangle .-.; drawthick- latex --.; tikzpicture center
Solution:
stackrelcurvearrowleftM stackrelcurvearrowrightM M_uparrow M_S + M_G F_uparrow ell_uparrow F_S ell_S + F_G ell_G F_uparrow ell'-x F_S leftfracell-xright + F_G ell-x F_uparrow ell'-F_uparrow x F_S fracell -F_S x + F_G ell-F_G x F_S x+F_G x-F_uparrow x F_S fracell + F_G ell-F_uparrow ell' F_S+F_G-F_uparrow x F_S fracell + F_G ell-F_uparrow ell' x fracF_S fracell + F_G ell-F_uparrow ell'F_S+F_G-F_uparrow .m
Meta Information
Exercise:
Am einen Ende einer drehbar gelagerten Stange g der Länge .dm sei ein Gewicht von .kg befestigt. cm von diesem Ende entfernt greife an der Stange ausserdem eine Kraft von N an. Berechne wie weit sich der Drehpunkt vom anderen Ende entfernt befindet siehe Skizze. center tikzpicture filldrawcolorblack fillblack!!white rectangle .; filldrawcolorblack .. circle .cm; drawsnakebrace .-.---.; node at .-. ?; draw ---.; drawthick colorblack .-. rectangle .-.; drawthick- latex --.; tikzpicture center
Solution:
stackrelcurvearrowleftM stackrelcurvearrowrightM M_uparrow M_S + M_G F_uparrow ell_uparrow F_S ell_S + F_G ell_G F_uparrow ell'-x F_S leftfracell-xright + F_G ell-x F_uparrow ell'-F_uparrow x F_S fracell -F_S x + F_G ell-F_G x F_S x+F_G x-F_uparrow x F_S fracell + F_G ell-F_uparrow ell' F_S+F_G-F_uparrow x F_S fracell + F_G ell-F_uparrow ell' x fracF_S fracell + F_G ell-F_uparrow ell'F_S+F_G-F_uparrow .m
Am einen Ende einer drehbar gelagerten Stange g der Länge .dm sei ein Gewicht von .kg befestigt. cm von diesem Ende entfernt greife an der Stange ausserdem eine Kraft von N an. Berechne wie weit sich der Drehpunkt vom anderen Ende entfernt befindet siehe Skizze. center tikzpicture filldrawcolorblack fillblack!!white rectangle .; filldrawcolorblack .. circle .cm; drawsnakebrace .-.---.; node at .-. ?; draw ---.; drawthick colorblack .-. rectangle .-.; drawthick- latex --.; tikzpicture center
Solution:
stackrelcurvearrowleftM stackrelcurvearrowrightM M_uparrow M_S + M_G F_uparrow ell_uparrow F_S ell_S + F_G ell_G F_uparrow ell'-x F_S leftfracell-xright + F_G ell-x F_uparrow ell'-F_uparrow x F_S fracell -F_S x + F_G ell-F_G x F_S x+F_G x-F_uparrow x F_S fracell + F_G ell-F_uparrow ell' F_S+F_G-F_uparrow x F_S fracell + F_G ell-F_uparrow ell' x fracF_S fracell + F_G ell-F_uparrow ell'F_S+F_G-F_uparrow .m
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Stange als einseitiger Hebel by TeXercises