Telefonmast
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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Video
\(\LaTeX\)
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Exercise:
Ein Telefonmast wird durch die Zugkraft der Telefonleitung mit siN beansprucht s. Abb. Wie gross sind die Kräfte auf den Mast und das Ankerseil? figureH centering tikzpicturelatexyscalexscal draw -- .; fill patternnorth east lines rectangle -.; fill .. circle .; filldraw fillbrown! . rectangle .; draw colorgray thick ..-- ; draw very thick .. -- . ; %draw thick .. -- ..; %draw -thick .. -- nodeleft vecF_M..; draw decorationbrace decorate .-. -- nodebelowyshift-.cm .sim -.; draw decorationbrace decorate . -- nodeleftxshift-.cm sim ..; tikzpicture figure
Solution:
Geg.: d.sim hsim FsiN Ges.: F_mathrmM und F_mathrmS Kräfte im Koordinatensystem: figureH centering tikzpicturelatex %Korrdinatensystem und Kräfteplan draw - --- noderightx; draw - -.--. nodeabovey; scopeyscalexscal draw -colorredthick -- -.nodeabove vecF ; %draw -thickcolorred --- nodeleft vecF_mathrmM; draw -thickcolorred -- nodeleft vecF_mathrmS .-; draw -colorOrangethick ---.- nodebelow vecF_mathrmSx; draw -colorOrangethick --noderight vecF_mathrmSy -; draw -colorBluethick --noderight vecF_mathrmN ; scope tikzpicture figure Die gesuchte Kraft F_mathrmM im Mast entspricht F_mathrmSy. Mit Verhältnis der Längen h und d erhalten wir F_mathrmSyF_mathrmM: frachdfracF_mathrmMFRa F_mathrmMfrachd FresN Und mit Pythagoras erhält man: F_mathrmSsqrtF^+F_mathrmM^resN
Ein Telefonmast wird durch die Zugkraft der Telefonleitung mit siN beansprucht s. Abb. Wie gross sind die Kräfte auf den Mast und das Ankerseil? figureH centering tikzpicturelatexyscalexscal draw -- .; fill patternnorth east lines rectangle -.; fill .. circle .; filldraw fillbrown! . rectangle .; draw colorgray thick ..-- ; draw very thick .. -- . ; %draw thick .. -- ..; %draw -thick .. -- nodeleft vecF_M..; draw decorationbrace decorate .-. -- nodebelowyshift-.cm .sim -.; draw decorationbrace decorate . -- nodeleftxshift-.cm sim ..; tikzpicture figure
Solution:
Geg.: d.sim hsim FsiN Ges.: F_mathrmM und F_mathrmS Kräfte im Koordinatensystem: figureH centering tikzpicturelatex %Korrdinatensystem und Kräfteplan draw - --- noderightx; draw - -.--. nodeabovey; scopeyscalexscal draw -colorredthick -- -.nodeabove vecF ; %draw -thickcolorred --- nodeleft vecF_mathrmM; draw -thickcolorred -- nodeleft vecF_mathrmS .-; draw -colorOrangethick ---.- nodebelow vecF_mathrmSx; draw -colorOrangethick --noderight vecF_mathrmSy -; draw -colorBluethick --noderight vecF_mathrmN ; scope tikzpicture figure Die gesuchte Kraft F_mathrmM im Mast entspricht F_mathrmSy. Mit Verhältnis der Längen h und d erhalten wir F_mathrmSyF_mathrmM: frachdfracF_mathrmMFRa F_mathrmMfrachd FresN Und mit Pythagoras erhält man: F_mathrmSsqrtF^+F_mathrmM^resN
Meta Information
Exercise:
Ein Telefonmast wird durch die Zugkraft der Telefonleitung mit siN beansprucht s. Abb. Wie gross sind die Kräfte auf den Mast und das Ankerseil? figureH centering tikzpicturelatexyscalexscal draw -- .; fill patternnorth east lines rectangle -.; fill .. circle .; filldraw fillbrown! . rectangle .; draw colorgray thick ..-- ; draw very thick .. -- . ; %draw thick .. -- ..; %draw -thick .. -- nodeleft vecF_M..; draw decorationbrace decorate .-. -- nodebelowyshift-.cm .sim -.; draw decorationbrace decorate . -- nodeleftxshift-.cm sim ..; tikzpicture figure
Solution:
Geg.: d.sim hsim FsiN Ges.: F_mathrmM und F_mathrmS Kräfte im Koordinatensystem: figureH centering tikzpicturelatex %Korrdinatensystem und Kräfteplan draw - --- noderightx; draw - -.--. nodeabovey; scopeyscalexscal draw -colorredthick -- -.nodeabove vecF ; %draw -thickcolorred --- nodeleft vecF_mathrmM; draw -thickcolorred -- nodeleft vecF_mathrmS .-; draw -colorOrangethick ---.- nodebelow vecF_mathrmSx; draw -colorOrangethick --noderight vecF_mathrmSy -; draw -colorBluethick --noderight vecF_mathrmN ; scope tikzpicture figure Die gesuchte Kraft F_mathrmM im Mast entspricht F_mathrmSy. Mit Verhältnis der Längen h und d erhalten wir F_mathrmSyF_mathrmM: frachdfracF_mathrmMFRa F_mathrmMfrachd FresN Und mit Pythagoras erhält man: F_mathrmSsqrtF^+F_mathrmM^resN
Ein Telefonmast wird durch die Zugkraft der Telefonleitung mit siN beansprucht s. Abb. Wie gross sind die Kräfte auf den Mast und das Ankerseil? figureH centering tikzpicturelatexyscalexscal draw -- .; fill patternnorth east lines rectangle -.; fill .. circle .; filldraw fillbrown! . rectangle .; draw colorgray thick ..-- ; draw very thick .. -- . ; %draw thick .. -- ..; %draw -thick .. -- nodeleft vecF_M..; draw decorationbrace decorate .-. -- nodebelowyshift-.cm .sim -.; draw decorationbrace decorate . -- nodeleftxshift-.cm sim ..; tikzpicture figure
Solution:
Geg.: d.sim hsim FsiN Ges.: F_mathrmM und F_mathrmS Kräfte im Koordinatensystem: figureH centering tikzpicturelatex %Korrdinatensystem und Kräfteplan draw - --- noderightx; draw - -.--. nodeabovey; scopeyscalexscal draw -colorredthick -- -.nodeabove vecF ; %draw -thickcolorred --- nodeleft vecF_mathrmM; draw -thickcolorred -- nodeleft vecF_mathrmS .-; draw -colorOrangethick ---.- nodebelow vecF_mathrmSx; draw -colorOrangethick --noderight vecF_mathrmSy -; draw -colorBluethick --noderight vecF_mathrmN ; scope tikzpicture figure Die gesuchte Kraft F_mathrmM im Mast entspricht F_mathrmSy. Mit Verhältnis der Längen h und d erhalten wir F_mathrmSyF_mathrmM: frachdfracF_mathrmMFRa F_mathrmMfrachd FresN Und mit Pythagoras erhält man: F_mathrmSsqrtF^+F_mathrmM^resN
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