Tritium-Deuterium Fusion
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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Exercise:
A deuterium isotopeH and a tritium isotopeH nucleus combine in a fusion reaction to form a helium nucleus isotopeHe leaving one excess neutron. Calculate the energy set free in this reaction abcliste abc using the binding energies. abc using the nuclear masses. abcliste
Solution:
abcliste abc The binding energies can be estimated from the diagram showing the average binding energy per nucleon. We find the following values: overlineE_BisotopeH BDO overlineE_BisotopeH BTO overlineE_BisotopeHe BHeO It follows for the energy set free in the fusion reaction Delta E dEBF NDtimesBD+NTtimesBT - NHetimesBHe resultdEBP abc The energy set free is equivalent to the mass defect Delta E dmBF mHe+mn &quad -mD+mT dmB resultdmBeVP abcliste The two results are compatible considering the rather large uncertay for the binding energies read from the diagram.
A deuterium isotopeH and a tritium isotopeH nucleus combine in a fusion reaction to form a helium nucleus isotopeHe leaving one excess neutron. Calculate the energy set free in this reaction abcliste abc using the binding energies. abc using the nuclear masses. abcliste
Solution:
abcliste abc The binding energies can be estimated from the diagram showing the average binding energy per nucleon. We find the following values: overlineE_BisotopeH BDO overlineE_BisotopeH BTO overlineE_BisotopeHe BHeO It follows for the energy set free in the fusion reaction Delta E dEBF NDtimesBD+NTtimesBT - NHetimesBHe resultdEBP abc The energy set free is equivalent to the mass defect Delta E dmBF mHe+mn &quad -mD+mT dmB resultdmBeVP abcliste The two results are compatible considering the rather large uncertay for the binding energies read from the diagram.
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Exercise:
A deuterium isotopeH and a tritium isotopeH nucleus combine in a fusion reaction to form a helium nucleus isotopeHe leaving one excess neutron. Calculate the energy set free in this reaction abcliste abc using the binding energies. abc using the nuclear masses. abcliste
Solution:
abcliste abc The binding energies can be estimated from the diagram showing the average binding energy per nucleon. We find the following values: overlineE_BisotopeH BDO overlineE_BisotopeH BTO overlineE_BisotopeHe BHeO It follows for the energy set free in the fusion reaction Delta E dEBF NDtimesBD+NTtimesBT - NHetimesBHe resultdEBP abc The energy set free is equivalent to the mass defect Delta E dmBF mHe+mn &quad -mD+mT dmB resultdmBeVP abcliste The two results are compatible considering the rather large uncertay for the binding energies read from the diagram.
A deuterium isotopeH and a tritium isotopeH nucleus combine in a fusion reaction to form a helium nucleus isotopeHe leaving one excess neutron. Calculate the energy set free in this reaction abcliste abc using the binding energies. abc using the nuclear masses. abcliste
Solution:
abcliste abc The binding energies can be estimated from the diagram showing the average binding energy per nucleon. We find the following values: overlineE_BisotopeH BDO overlineE_BisotopeH BTO overlineE_BisotopeHe BHeO It follows for the energy set free in the fusion reaction Delta E dEBF NDtimesBD+NTtimesBT - NHetimesBHe resultdEBP abc The energy set free is equivalent to the mass defect Delta E dmBF mHe+mn &quad -mD+mT dmB resultdmBeVP abcliste The two results are compatible considering the rather large uncertay for the binding energies read from the diagram.
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Bei Kernreaktion freigesetzte Energie by TeXercises
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Relativistic Dynamics by by
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