Verhältnis
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
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Visit our YouTube-Channel to see solutions to other exercises.
Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
In welchem Verhältnis müsste man Wasser der Temperatur +°C und Eis von –°C in einem gut isolierten Gefäss mischen damit das Wasser gerade noch vollständig gefriert?
Solution:
Heisses Wasser abkühlen: Q_c_W m_W Delta T_W Dann gefrieren: Q_L_f m_W Eis ebenfalls auf null Grad bringen: Q_c_E m_E Delta T_E Abgegebene Wärme gleich aufgenommene Wärme: Q_+Q_Q_ Ausserdem gilt: Delta TDelta T_WDelta T_E Also: c m_W Delta T +L_f m_W c_E m_E Delta T rightarrow m_W c_W Delta T +L_f c_E m_E Delta T rightarrow fracm_Em_W fracc_W Delta T +L_fc_E Delta T frac fracJkgK K+. ^ fracJkg fracJkgK K &approx Also etwa -mal mehr Eis.
In welchem Verhältnis müsste man Wasser der Temperatur +°C und Eis von –°C in einem gut isolierten Gefäss mischen damit das Wasser gerade noch vollständig gefriert?
Solution:
Heisses Wasser abkühlen: Q_c_W m_W Delta T_W Dann gefrieren: Q_L_f m_W Eis ebenfalls auf null Grad bringen: Q_c_E m_E Delta T_E Abgegebene Wärme gleich aufgenommene Wärme: Q_+Q_Q_ Ausserdem gilt: Delta TDelta T_WDelta T_E Also: c m_W Delta T +L_f m_W c_E m_E Delta T rightarrow m_W c_W Delta T +L_f c_E m_E Delta T rightarrow fracm_Em_W fracc_W Delta T +L_fc_E Delta T frac fracJkgK K+. ^ fracJkg fracJkgK K &approx Also etwa -mal mehr Eis.
Meta Information
Exercise:
In welchem Verhältnis müsste man Wasser der Temperatur +°C und Eis von –°C in einem gut isolierten Gefäss mischen damit das Wasser gerade noch vollständig gefriert?
Solution:
Heisses Wasser abkühlen: Q_c_W m_W Delta T_W Dann gefrieren: Q_L_f m_W Eis ebenfalls auf null Grad bringen: Q_c_E m_E Delta T_E Abgegebene Wärme gleich aufgenommene Wärme: Q_+Q_Q_ Ausserdem gilt: Delta TDelta T_WDelta T_E Also: c m_W Delta T +L_f m_W c_E m_E Delta T rightarrow m_W c_W Delta T +L_f c_E m_E Delta T rightarrow fracm_Em_W fracc_W Delta T +L_fc_E Delta T frac fracJkgK K+. ^ fracJkg fracJkgK K &approx Also etwa -mal mehr Eis.
In welchem Verhältnis müsste man Wasser der Temperatur +°C und Eis von –°C in einem gut isolierten Gefäss mischen damit das Wasser gerade noch vollständig gefriert?
Solution:
Heisses Wasser abkühlen: Q_c_W m_W Delta T_W Dann gefrieren: Q_L_f m_W Eis ebenfalls auf null Grad bringen: Q_c_E m_E Delta T_E Abgegebene Wärme gleich aufgenommene Wärme: Q_+Q_Q_ Ausserdem gilt: Delta TDelta T_WDelta T_E Also: c m_W Delta T +L_f m_W c_E m_E Delta T rightarrow m_W c_W Delta T +L_f c_E m_E Delta T rightarrow fracm_Em_W fracc_W Delta T +L_fc_E Delta T frac fracJkgK K+. ^ fracJkg fracJkgK K &approx Also etwa -mal mehr Eis.
Contained in these collections
| Title | Creator | Matched on |
|---|---|---|
| Frostschutzberegnung | sn | tags |
| Verhältnis | uz | title |
| Bergsteigen | sn | tags |
| Bilanz: Dampf und Eis | sn | tags |
| Vergleich Latenter Wärmen | sn | tags |
Similar exercises (6)
| Title | Creator | Matched on |
|---|---|---|
| Frostschutzberegnung | sn | tags |
| Verhältnis | uz | title |
| Bergsteigen | sn | tags |
| Bilanz: Dampf und Eis | sn | tags |
| Vergleich Latenter Wärmen | sn | tags |
| Suppe | sn | tags |

