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Exercise:
After an increase of the acceleration voltage the particles in an accelerator gain vincO more speed. Determine the corresponding increase in acceleration voltage.

Solution:
The acceleration voltage is proportional to the square of the final velocity: Delta phi varpropto v^ The ratio of the new to the old acceleration voltage therefore is fracDelta phi'Delta phi VfF leftfracvfSright^ resultVfS The percentage increase of the acceleration voltage is VincpercP.
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Exercise:
After an increase of the acceleration voltage the particles in an accelerator gain vincO more speed. Determine the corresponding increase in acceleration voltage.

Solution:
The acceleration voltage is proportional to the square of the final velocity: Delta phi varpropto v^ The ratio of the new to the old acceleration voltage therefore is fracDelta phi'Delta phi VfF leftfracvfSright^ resultVfS The percentage increase of the acceleration voltage is VincpercP.
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Branches
Electrostatics
Tags
acceleration voltage, electrostatics, potential difference, voltage
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Difficulty
(2, default)
Points
0 (default)
Language
ENG (English)
Type
Calculative / Quantity
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