Compass next to cable
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
Need help? Yes, please!
The following quantities appear in the problem:
elektrische Stromstärke \(I\) / Magnetische Flussdichte \(B\) / Winkel \(\theta\) /
The following formulas must be used to solve the exercise:
\(B = \dfrac{\mu_0 I}{2\pi r} \quad \) \(\tan\alpha = \dfrac{a}{b} \quad \)
No explanation / solution video to this exercise has yet been created.
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Visit our YouTube-Channel to see solutions to other exercises.
Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
A compass is placed rO south of a cable carrying a current IO from top to bottom. Calculate the angle by which the compass needle is deflected if the horizontal component of the Earth's magnetic field at this po is BeO.
Solution:
center tikzpicture nodecolorOrange at bigotimes; nodecolorOrange at . I; drawcolorblue dashed circle cm; drawgreen - latex -.----. nodeleft midway r; drawultra thick red - stealth ----.; drawultra thick green -.---; tikzpicture center Geg r rO r I I sscBE BeO Be GesAnglealphasirad At a distance of rO the strength of the conductor magnetic field is al sscBL fracmu_ Ipi r fracncmu Ipi r Bl. At the location of the compass needle the Earth's magnetic field sscBE acts from geographically south to north and the conductor magnetic field sscBL acts from east to west. The two magnetic fields form the opposite sides of a right-angled triangle. The angle is therefore al alpha arctanfracsscBLsscBE arctanfracfracmu_ Ipi rsscBE arctanfracmu_Ipi r sscBE fracBlBe adP arS arP towards the west. % a arctanfracmu_Ipi r sscBE adP arS arP
A compass is placed rO south of a cable carrying a current IO from top to bottom. Calculate the angle by which the compass needle is deflected if the horizontal component of the Earth's magnetic field at this po is BeO.
Solution:
center tikzpicture nodecolorOrange at bigotimes; nodecolorOrange at . I; drawcolorblue dashed circle cm; drawgreen - latex -.----. nodeleft midway r; drawultra thick red - stealth ----.; drawultra thick green -.---; tikzpicture center Geg r rO r I I sscBE BeO Be GesAnglealphasirad At a distance of rO the strength of the conductor magnetic field is al sscBL fracmu_ Ipi r fracncmu Ipi r Bl. At the location of the compass needle the Earth's magnetic field sscBE acts from geographically south to north and the conductor magnetic field sscBL acts from east to west. The two magnetic fields form the opposite sides of a right-angled triangle. The angle is therefore al alpha arctanfracsscBLsscBE arctanfracfracmu_ Ipi rsscBE arctanfracmu_Ipi r sscBE fracBlBe adP arS arP towards the west. % a arctanfracmu_Ipi r sscBE adP arS arP
Meta Information
Exercise:
A compass is placed rO south of a cable carrying a current IO from top to bottom. Calculate the angle by which the compass needle is deflected if the horizontal component of the Earth's magnetic field at this po is BeO.
Solution:
center tikzpicture nodecolorOrange at bigotimes; nodecolorOrange at . I; drawcolorblue dashed circle cm; drawgreen - latex -.----. nodeleft midway r; drawultra thick red - stealth ----.; drawultra thick green -.---; tikzpicture center Geg r rO r I I sscBE BeO Be GesAnglealphasirad At a distance of rO the strength of the conductor magnetic field is al sscBL fracmu_ Ipi r fracncmu Ipi r Bl. At the location of the compass needle the Earth's magnetic field sscBE acts from geographically south to north and the conductor magnetic field sscBL acts from east to west. The two magnetic fields form the opposite sides of a right-angled triangle. The angle is therefore al alpha arctanfracsscBLsscBE arctanfracfracmu_ Ipi rsscBE arctanfracmu_Ipi r sscBE fracBlBe adP arS arP towards the west. % a arctanfracmu_Ipi r sscBE adP arS arP
A compass is placed rO south of a cable carrying a current IO from top to bottom. Calculate the angle by which the compass needle is deflected if the horizontal component of the Earth's magnetic field at this po is BeO.
Solution:
center tikzpicture nodecolorOrange at bigotimes; nodecolorOrange at . I; drawcolorblue dashed circle cm; drawgreen - latex -.----. nodeleft midway r; drawultra thick red - stealth ----.; drawultra thick green -.---; tikzpicture center Geg r rO r I I sscBE BeO Be GesAnglealphasirad At a distance of rO the strength of the conductor magnetic field is al sscBL fracmu_ Ipi r fracncmu Ipi r Bl. At the location of the compass needle the Earth's magnetic field sscBE acts from geographically south to north and the conductor magnetic field sscBL acts from east to west. The two magnetic fields form the opposite sides of a right-angled triangle. The angle is therefore al alpha arctanfracsscBLsscBE arctanfracfracmu_ Ipi rsscBE arctanfracmu_Ipi r sscBE fracBlBe adP arS arP towards the west. % a arctanfracmu_Ipi r sscBE adP arS arP
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Magnetfeldkomponente gerader Leiter by TeXercises
Asked Quantity:
Winkel \(\theta\)
in
Radian \(\rm rad\)
Physical Quantity
Unit
Radian (\(\rm rad\))
Base?
SI?
Metric?
Coherent?
Imperial?