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Gefundene Holzaxt

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Level 5 -
Level 6 -

Exercise

https://texercises.com/exercise/gefundene-holzaxt/

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The following quantities appear in the problem: Zeit \(t\) / Masse \(m\) / Aktivität \(A\) / Halbwertszeit \(T\) / Zerfallskonstante \(\lambda\) /

The following formulas must be used to solve the exercise: \(A = m \hat A \quad \) \(A_t = A_0 \cdot \text{e}^{-\lambda t} \quad \) \(A_t = A_0 \cdot2^{-\frac{t}{T}} \quad \)

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Exercise:
Wie viel Masse Kohlenstoff müsste man einer gefundenen Holzaxt entnehmen welche man aufgrund archäologischer Hinweise auf ein Alter von etwa tO schätzt um in dieser Probe noch rund AtO aufgrund von isotopeC-Zerfällen mit TO Halbwertszeit festzustellen? Frischer Kohlenstoff hat etwa hAzO Aktivität.

Solution:
Geg t tO t A_t AtO At widehat A_ hAzO hAz GesMassemsikg Die Probe musste damals frisch SolQtyAzAtX*^tX/TXBq A_ A_t ^+fractT A_t texte^+lambda t At ^+fractT Az Aktivität haben. Das entspricht SolQtymAzX/hAzXkg m fracA_widehat A_ fracA_t ^+fractTwidehat A_ fracA_twidehat A_ ^+fractT fracAzhAz m approx mS mP Kohlenstoff. m fracA_twidehat A_ ^+fractT mS mP

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Contained in these collections:

C14-Methode by TeXercises

9 | 21

Asked Quantity: Masse \(m\) in Kilogramm \(\rm kg\)

Attributes & Decorations

Tags	altersbestimmung, c-14-methode, kernphysik, physik, radioaktivität, radiocarbon
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Difficulty	(2, default)
Points	5 (default)
Language	(Deutsch)
Type	Calculative / Quantity
Creator	uz
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