Halbwertszeit von Polonium
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
Need help? Yes, please!
The following quantities appear in the problem:
Zeit \(t\) / Masse \(m\) / molare Masse \(M\) / Stoffmenge \(n\) / Zerfallskonstante \(\lambda\) / Anzahl \(N\) /
The following formulas must be used to solve the exercise:
\(m = nM \quad \) \(N_t = N_0 \cdot \text{e}^{-\lambda t} \quad \)
No explanation / solution video to this exercise has yet been created.
Visit our YouTube-Channel to see solutions to other exercises.
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Visit our YouTube-Channel to see solutions to other exercises.
Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
Das radioaktive Nuklid isotopePo zerfällt nach der Kernreaktionsformel isotopePo rightarrow isotopePb + isotopeHe. Berechne die Halbwertszeit von isotopePo wenn aus mPoO dieses Stoffes innert tO etwa mHeO Helium- entstehen.
Solution:
Die angegebene Menge des entstandenen Heliums entspricht etwa Delta n fracmM fracmHeMHe dn Delta N n sscNA dN Teilchen Helium. Die Anfangsmenge des Polonium-Isotopes entspricht nach derselben Rechnung folger Teilchenmenge: n_ fracm_M fracmPoMPo nPo N_ n_ N_A NPo Nach Ablauf von tO sind also noch N_t N_-Delta N NPo - dN Nt Teilchen Polonium vorhanden. Mittels Zerfallsgesetz findet man die Zerfallskonstante und Halbwertszeit dieses Polonium-Isotopes: lambda fract ln leftfracN_N_tright lam T fracln lambda T
Das radioaktive Nuklid isotopePo zerfällt nach der Kernreaktionsformel isotopePo rightarrow isotopePb + isotopeHe. Berechne die Halbwertszeit von isotopePo wenn aus mPoO dieses Stoffes innert tO etwa mHeO Helium- entstehen.
Solution:
Die angegebene Menge des entstandenen Heliums entspricht etwa Delta n fracmM fracmHeMHe dn Delta N n sscNA dN Teilchen Helium. Die Anfangsmenge des Polonium-Isotopes entspricht nach derselben Rechnung folger Teilchenmenge: n_ fracm_M fracmPoMPo nPo N_ n_ N_A NPo Nach Ablauf von tO sind also noch N_t N_-Delta N NPo - dN Nt Teilchen Polonium vorhanden. Mittels Zerfallsgesetz findet man die Zerfallskonstante und Halbwertszeit dieses Polonium-Isotopes: lambda fract ln leftfracN_N_tright lam T fracln lambda T
Meta Information
Exercise:
Das radioaktive Nuklid isotopePo zerfällt nach der Kernreaktionsformel isotopePo rightarrow isotopePb + isotopeHe. Berechne die Halbwertszeit von isotopePo wenn aus mPoO dieses Stoffes innert tO etwa mHeO Helium- entstehen.
Solution:
Die angegebene Menge des entstandenen Heliums entspricht etwa Delta n fracmM fracmHeMHe dn Delta N n sscNA dN Teilchen Helium. Die Anfangsmenge des Polonium-Isotopes entspricht nach derselben Rechnung folger Teilchenmenge: n_ fracm_M fracmPoMPo nPo N_ n_ N_A NPo Nach Ablauf von tO sind also noch N_t N_-Delta N NPo - dN Nt Teilchen Polonium vorhanden. Mittels Zerfallsgesetz findet man die Zerfallskonstante und Halbwertszeit dieses Polonium-Isotopes: lambda fract ln leftfracN_N_tright lam T fracln lambda T
Das radioaktive Nuklid isotopePo zerfällt nach der Kernreaktionsformel isotopePo rightarrow isotopePb + isotopeHe. Berechne die Halbwertszeit von isotopePo wenn aus mPoO dieses Stoffes innert tO etwa mHeO Helium- entstehen.
Solution:
Die angegebene Menge des entstandenen Heliums entspricht etwa Delta n fracmM fracmHeMHe dn Delta N n sscNA dN Teilchen Helium. Die Anfangsmenge des Polonium-Isotopes entspricht nach derselben Rechnung folger Teilchenmenge: n_ fracm_M fracmPoMPo nPo N_ n_ N_A NPo Nach Ablauf von tO sind also noch N_t N_-Delta N NPo - dN Nt Teilchen Polonium vorhanden. Mittels Zerfallsgesetz findet man die Zerfallskonstante und Halbwertszeit dieses Polonium-Isotopes: lambda fract ln leftfracN_N_tright lam T fracln lambda T
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Zerfallsgleichung by TeXercises
Asked Quantity:
Halbwertszeit \(T\)
in
Sekunde \(\rm s\)
Physical Quantity
Hälfte der Kerne zerfallen
Unit
Seit 1967 ist eine Sekunde das 9.192.631.770-fache der Periodendauer der Strahlung, die dem Übergang zwischen den beiden Hyperfeinstrukturniveaus des Grundzustandes von Atomen des Nuklids 133Cs entspricht.
Base?
SI?
Metric?
Coherent?
Imperial?