Exercise
https://texercises.com/exercise/internal-resistance/
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The following quantities appear in the problem: elektrische Stromstärke \(I\) / elektrische Spannung \(U\) / elektrischer Widerstand \(R\) /
The following formulas must be used to solve the exercise: \(U=RI \quad \)
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Exercise:
A battery with an source voltage of VSO and an ernal resistance of RiO. It is connected to a light bulb with resistance RLO. Calculate the current in the circuit and the power dissipated in the light bulb.

Solution:
abcliste abc The total resistance of the two resistors in series is given by sscRtot R_i + R_L The current is I fracDelta VsscRtot IF fracVSRi+RL I approx resultIP abc The power dissipated in the light bulb can be calculated as P_L R_L I^ PLF fracleftVSright^timesRileftRi+RLright^ PL approx resultPLP abcliste
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Exercise:
A battery with an source voltage of VSO and an ernal resistance of RiO. It is connected to a light bulb with resistance RLO. Calculate the current in the circuit and the power dissipated in the light bulb.

Solution:
abcliste abc The total resistance of the two resistors in series is given by sscRtot R_i + R_L The current is I fracDelta VsscRtot IF fracVSRi+RL I approx resultIP abc The power dissipated in the light bulb can be calculated as P_L R_L I^ PLF fracleftVSright^timesRileftRi+RLright^ PL approx resultPLP abcliste
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  1. Innenwiderstand by TeXercises
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Branches
Direct Current
Tags
internal resistance, resistor, resistor circuit, series resistors
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Difficulty
(1, default)
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0 (default)
Language
ENG (English)
Type
Calculative / Quantity
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