Exercise
https://texercises.com/exercise/laboratory-worker/
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The following quantities appear in the problem: Zeit \(t\) / Masse \(m\) / Energie \(E\) / Aktivität \(A\) / Äquivalentdosis \(H\) / Radius \(r\) / Oberfläche \(S\) / Zerfallskonstante \(\lambda\) / Energiedosis \(D\) /
The following formulas must be used to solve the exercise: \(D = \dfrac{E}{m} \quad \) \(S = 4 \pi r^2 \quad \) \(A_t = A_0 \cdot \text{e}^{-\lambda t} \quad \) \(H = qD \quad \)
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Exercise:
What wholbody dose is received by a mO laboratory worker exposed to a AO Ci.eBq isotopeCo source asing the person's body has a cross-sectional area SpO and is normally about rO from the source for tO per day? isotopeCo emits upgamma rays of energy EaO and EbO in quick succession. Approximately netO of the upgamma rays eract in the body and deposit all their energy. The rest passes through.

Solution:
Geg m mO A AO A S' Sp r rO r t tO t upgamma rightarrow w wO E_ EaO Ea E_ EbO Eb eta netO net Gesequivalent doseHsiSv The Cobalt source radiates its activity uniformely distributed in all directions - i.e. o a sphere with S pi r^ pi qtyr^ S. Since the body has a cross-sectional area of SpO he is hit by the activity tilde A A fracS'S A fracS'pi r^ A fracSpSu tA of which only netO eract with the body i.e. A' eta tilde A eta fracAS'pi r^ net tA Ap. During tO of work the body of the worker absorbes the energy E t A' E_+E_ t eta fracAS'pi r^ E_+E_ t Ap Ea+Eb E The absorbed dose therefore is D fracEm fracm fraceta tAS'pi r^ E_+E_ fracEm D Since upgamma-rays have a radiation quality factor of q the wholbody dose is H wD w fraceta tAS'E_+E_pi m r^ w D H approx HS HP-. H fraceta twAS'E_+E_pi m r^ HS HP-
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Exercise:
What wholbody dose is received by a mO laboratory worker exposed to a AO Ci.eBq isotopeCo source asing the person's body has a cross-sectional area SpO and is normally about rO from the source for tO per day? isotopeCo emits upgamma rays of energy EaO and EbO in quick succession. Approximately netO of the upgamma rays eract in the body and deposit all their energy. The rest passes through.

Solution:
Geg m mO A AO A S' Sp r rO r t tO t upgamma rightarrow w wO E_ EaO Ea E_ EbO Eb eta netO net Gesequivalent doseHsiSv The Cobalt source radiates its activity uniformely distributed in all directions - i.e. o a sphere with S pi r^ pi qtyr^ S. Since the body has a cross-sectional area of SpO he is hit by the activity tilde A A fracS'S A fracS'pi r^ A fracSpSu tA of which only netO eract with the body i.e. A' eta tilde A eta fracAS'pi r^ net tA Ap. During tO of work the body of the worker absorbes the energy E t A' E_+E_ t eta fracAS'pi r^ E_+E_ t Ap Ea+Eb E The absorbed dose therefore is D fracEm fracm fraceta tAS'pi r^ E_+E_ fracEm D Since upgamma-rays have a radiation quality factor of q the wholbody dose is H wD w fraceta tAS'E_+E_pi m r^ w D H approx HS HP-. H fraceta twAS'E_+E_pi m r^ HS HP-
Contained in these collections:
  1. 8 | 8
  2. Whole-body dose by TeXercises
    1 | 4
  3. 3 | 6


Attributes & Decorations
Branches
Work, Energy, Power
Tags
absorption, bequerel, cobalt, curie, decay, dose, dosimetry, energy, gamma, mev, nuclear, physics, radiation, radioactivity, ray, rays, sievert
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Difficulty
(3, default)
Points
6 (default)
Language
ENG (English)
Type
Calculative / Quantity
Creator uz
Decoration
File
Link