Exercise
https://texercises.com/exercise/length-of-a-copper-wire/
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The following quantities appear in the problem: Masse \(m\) / Volumen \(V\) / Höhe \(h\) / Radius \(r\) / Dichte \(\varrho\) /
The following formulas must be used to solve the exercise: \(\varrho = \dfrac{m}{V} \quad \) \(V = \pi r^2 \cdot h \quad \)
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Exercise:
A wire made of copper rO has mO mass and the radius of its circular cross-sectional area is RO. How long is the wire? One ounce is .g.

Solution:
Geg rho rO r m mO m r RO R GesLengthellsim The wire has SolQtyVmX/rXcubicmeter V fracmrho fracmr V volume. So the length of the wire -- actually a high cylinder -- is: SolQtylVX/pi/RX^m ell fracVpi r^ fracmrho pi r^ fracVpi qtyR^ l ell fracmrho pi r^ l
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Exercise:
A wire made of copper rO has mO mass and the radius of its circular cross-sectional area is RO. How long is the wire? One ounce is .g.

Solution:
Geg rho rO r m mO m r RO R GesLengthellsim The wire has SolQtyVmX/rXcubicmeter V fracmrho fracmr V volume. So the length of the wire -- actually a high cylinder -- is: SolQtylVX/pi/RX^m ell fracVpi r^ fracmrho pi r^ fracVpi qtyR^ l ell fracmrho pi r^ l
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Tags
copper, cylinder, density, length, mass, mechanics, physics, volume, wire
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Difficulty
(2, default)
Points
2 (default)
Language
ENG (English)
Type
Calculative / Quantity
Creator uz
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Link