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The following quantities appear in the problem: Länge \ell / elektrischer Widerstand RR / Fläche AA / spezifischer elektrischer Widerstand ρ\rho /
The following formulas must be used to solve the exercise: R=ϱAR = \varrho \dfrac{\ell}{A} \quad
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Exercise:
A wire LO long and with diameter dO has a resistance of RO. What material could it be made of?

Solution:
The resistance of a wire is given by R sscrhoelfracLA Solving for the resistivity leads to sscrhoel rF fracRtimesd^times pitimesL r approx resultrP- This is close to the resistivity of iron.
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Exercise:
A wire LO long and with diameter dO has a resistance of RO. What material could it be made of?

Solution:
The resistance of a wire is given by R sscrhoelfracLA Solving for the resistivity leads to sscrhoel rF fracRtimesd^times pitimesL r approx resultrP- This is close to the resistivity of iron.
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Direct Current
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resistance, resistivity
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ENG (English)
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Calculative / Quantity
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