Exercise
https://texercises.com/exercise/silver-wire/
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The following quantities appear in the problem: Länge \(\ell\) / elektrischer Widerstand \(R\) / Fläche \(A\) / spezifischer elektrischer Widerstand \(\rho\) /
The following formulas must be used to solve the exercise: \(R = \varrho \dfrac{\ell}{A} \quad \)
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Exercise:
A silver wire has a cross sectional area of AO and RO resistance. How long is the wire?

Solution:
The resistance of a wire is given by R sscrhoelfracLA Solving for the length leads to L LF fracRtimesAr L approx resultLP
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Exercise:
A silver wire has a cross sectional area of AO and RO resistance. How long is the wire?

Solution:
The resistance of a wire is given by R sscrhoelfracLA Solving for the length leads to L LF fracRtimesAr L approx resultLP
Contained in these collections:
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  2. 18 | 19

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Direct Current
Tags
resistance, resistivity
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Difficulty
(1, default)
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0 (default)
Language
ENG (English)
Type
Calculative / Quantity
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