Rollender Zylinder
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
Need help? Yes, please!
The following quantities appear in the problem:
Zeit \(t\) / Radius \(r\) / Winkelgeschwindigkeit / Kreisfrequenz \(\omega\) / Winkelbeschleunigung \(\alpha\) / Winkel \(\theta\) /
The following formulas must be used to solve the exercise:
\(\gamma = \dfrac{\alpha}{2}t^2+\omega_0 t + \gamma_0 \quad \) \(b = r \gamma \quad \)
No explanation / solution video to this exercise has yet been created.
Visit our YouTube-Channel to see solutions to other exercises.
Don't forget to subscribe to our channel, like the videos and leave comments!
Visit our YouTube-Channel to see solutions to other exercises.
Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
Ein Zylinder mit .cm Durchmesser rolle auf einer horizontalen Fläche mit einer Win-kel-gschwin-dig-keit von .radianpersecond bevor er auf eine anschliesse leicht geneigte Fläche rollt auf welcher er .radianpersecondsquared Win-kel-bschleu-ni-gung erfährt. Wie lange dauert es bis der Zylinder auf der schiefen Ebene cm zurückgelegt hat?
Solution:
newqtyd.m newqtyv.rps newqtya.rpss newqtysm % Geg d .cm d omega_ v alpha a b cm s % GesZeittsis % Der überstrichene Winkel s ist die Bogenlänge entspricht solqtygafracsd*sn/dnrad al gamma fracsr gaf frac sd ga. Die benötigte Zeit sich um diesen Winkel zu drehen beträgt solqtytfrac-omega_d pm sqrtomega_^d^+alpha dsalpha d-vn+sqrtvn**+*an*gan/ans solqtytmfrac-omega_d - sqrtomega_^d^+alpha dsalpha d-vn-sqrtvn**+*an*gan/ans al t frac-omega_ pm sqrtomega_^+alphagammaalpha tf frac-qtyv pm sqrtqtyv^+agaa rightarrow t_ t approx Scit t_ tm approx Scitm % t tf Scit
Ein Zylinder mit .cm Durchmesser rolle auf einer horizontalen Fläche mit einer Win-kel-gschwin-dig-keit von .radianpersecond bevor er auf eine anschliesse leicht geneigte Fläche rollt auf welcher er .radianpersecondsquared Win-kel-bschleu-ni-gung erfährt. Wie lange dauert es bis der Zylinder auf der schiefen Ebene cm zurückgelegt hat?
Solution:
newqtyd.m newqtyv.rps newqtya.rpss newqtysm % Geg d .cm d omega_ v alpha a b cm s % GesZeittsis % Der überstrichene Winkel s ist die Bogenlänge entspricht solqtygafracsd*sn/dnrad al gamma fracsr gaf frac sd ga. Die benötigte Zeit sich um diesen Winkel zu drehen beträgt solqtytfrac-omega_d pm sqrtomega_^d^+alpha dsalpha d-vn+sqrtvn**+*an*gan/ans solqtytmfrac-omega_d - sqrtomega_^d^+alpha dsalpha d-vn-sqrtvn**+*an*gan/ans al t frac-omega_ pm sqrtomega_^+alphagammaalpha tf frac-qtyv pm sqrtqtyv^+agaa rightarrow t_ t approx Scit t_ tm approx Scitm % t tf Scit
Meta Information
Exercise:
Ein Zylinder mit .cm Durchmesser rolle auf einer horizontalen Fläche mit einer Win-kel-gschwin-dig-keit von .radianpersecond bevor er auf eine anschliesse leicht geneigte Fläche rollt auf welcher er .radianpersecondsquared Win-kel-bschleu-ni-gung erfährt. Wie lange dauert es bis der Zylinder auf der schiefen Ebene cm zurückgelegt hat?
Solution:
newqtyd.m newqtyv.rps newqtya.rpss newqtysm % Geg d .cm d omega_ v alpha a b cm s % GesZeittsis % Der überstrichene Winkel s ist die Bogenlänge entspricht solqtygafracsd*sn/dnrad al gamma fracsr gaf frac sd ga. Die benötigte Zeit sich um diesen Winkel zu drehen beträgt solqtytfrac-omega_d pm sqrtomega_^d^+alpha dsalpha d-vn+sqrtvn**+*an*gan/ans solqtytmfrac-omega_d - sqrtomega_^d^+alpha dsalpha d-vn-sqrtvn**+*an*gan/ans al t frac-omega_ pm sqrtomega_^+alphagammaalpha tf frac-qtyv pm sqrtqtyv^+agaa rightarrow t_ t approx Scit t_ tm approx Scitm % t tf Scit
Ein Zylinder mit .cm Durchmesser rolle auf einer horizontalen Fläche mit einer Win-kel-gschwin-dig-keit von .radianpersecond bevor er auf eine anschliesse leicht geneigte Fläche rollt auf welcher er .radianpersecondsquared Win-kel-bschleu-ni-gung erfährt. Wie lange dauert es bis der Zylinder auf der schiefen Ebene cm zurückgelegt hat?
Solution:
newqtyd.m newqtyv.rps newqtya.rpss newqtysm % Geg d .cm d omega_ v alpha a b cm s % GesZeittsis % Der überstrichene Winkel s ist die Bogenlänge entspricht solqtygafracsd*sn/dnrad al gamma fracsr gaf frac sd ga. Die benötigte Zeit sich um diesen Winkel zu drehen beträgt solqtytfrac-omega_d pm sqrtomega_^d^+alpha dsalpha d-vn+sqrtvn**+*an*gan/ans solqtytmfrac-omega_d - sqrtomega_^d^+alpha dsalpha d-vn-sqrtvn**+*an*gan/ans al t frac-omega_ pm sqrtomega_^+alphagammaalpha tf frac-qtyv pm sqrtqtyv^+agaa rightarrow t_ t approx Scit t_ tm approx Scitm % t tf Scit
Contained in these collections:
-
Kinematik am Kreis by pw
-
Bogenlänge und 1. Formel mit Anfangsgeschwindigkeit by TeXercises
-
Asked Quantity:
Zeit \(t\)
in
Sekunde \(\rm s\)
Physical Quantity
Die Zeit beschreibt die Abfolge von Ereignissen, hat also eine eindeutige, nicht umkehrbare Richtung.
Unit
Seit 1967 ist eine Sekunde das 9.192.631.770-fache der Periodendauer der Strahlung, die dem Übergang zwischen den beiden Hyperfeinstrukturniveaus des Grundzustandes von Atomen des Nuklids 133Cs entspricht.
Base?
SI?
Metric?
Coherent?
Imperial?