Simple Harmonic Motion
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
No explanation / solution video to this exercise has yet been created.
Visit our YouTube-Channel to see solutions to other exercises.
Don't forget to subscribe to our channel, like the videos and leave comments!
Visit our YouTube-Channel to see solutions to other exercises.
Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
The differential of a simple harmonic oscillator ddot y -omega_^ y can be erpreted as a system of two linear first-order differential s. The eigenvalues and eigenvectors are given by lambda_ pm iomega_ vec v_ pmatrix mp i omega_ pmatrix vspacemm Show that the function yt sinomega_ t is the solution for the initial conditions y quad textrmand quad dot y omega_
Solution:
The solution y_t is a superposition of the fundamental solutions: pmatrix y_t dot y_t pmatrix a_ vec v_ e^lambda_ t + a_ vec v_ e^lambda_ t For t we find y_ a_ -i+a_ i -i a_-a_ Longrightarrow a_ a_ dot y_ omega_ a_ omega_ + a_ omega_ omega_ a_+a_ Longrightarrow a_ + a_ a_ Longrightarrow a_ a_ frac It follows that y_t fracleft-i e^iomega_ t+i e^-iomega_ tright -fracilefte^iomega_ t-e^-iomega_ tright -fraci isinomega_ t -i^ sinomega_ t sinomega_ t
The differential of a simple harmonic oscillator ddot y -omega_^ y can be erpreted as a system of two linear first-order differential s. The eigenvalues and eigenvectors are given by lambda_ pm iomega_ vec v_ pmatrix mp i omega_ pmatrix vspacemm Show that the function yt sinomega_ t is the solution for the initial conditions y quad textrmand quad dot y omega_
Solution:
The solution y_t is a superposition of the fundamental solutions: pmatrix y_t dot y_t pmatrix a_ vec v_ e^lambda_ t + a_ vec v_ e^lambda_ t For t we find y_ a_ -i+a_ i -i a_-a_ Longrightarrow a_ a_ dot y_ omega_ a_ omega_ + a_ omega_ omega_ a_+a_ Longrightarrow a_ + a_ a_ Longrightarrow a_ a_ frac It follows that y_t fracleft-i e^iomega_ t+i e^-iomega_ tright -fracilefte^iomega_ t-e^-iomega_ tright -fraci isinomega_ t -i^ sinomega_ t sinomega_ t
Meta Information
Exercise:
The differential of a simple harmonic oscillator ddot y -omega_^ y can be erpreted as a system of two linear first-order differential s. The eigenvalues and eigenvectors are given by lambda_ pm iomega_ vec v_ pmatrix mp i omega_ pmatrix vspacemm Show that the function yt sinomega_ t is the solution for the initial conditions y quad textrmand quad dot y omega_
Solution:
The solution y_t is a superposition of the fundamental solutions: pmatrix y_t dot y_t pmatrix a_ vec v_ e^lambda_ t + a_ vec v_ e^lambda_ t For t we find y_ a_ -i+a_ i -i a_-a_ Longrightarrow a_ a_ dot y_ omega_ a_ omega_ + a_ omega_ omega_ a_+a_ Longrightarrow a_ + a_ a_ Longrightarrow a_ a_ frac It follows that y_t fracleft-i e^iomega_ t+i e^-iomega_ tright -fracilefte^iomega_ t-e^-iomega_ tright -fraci isinomega_ t -i^ sinomega_ t sinomega_ t
The differential of a simple harmonic oscillator ddot y -omega_^ y can be erpreted as a system of two linear first-order differential s. The eigenvalues and eigenvectors are given by lambda_ pm iomega_ vec v_ pmatrix mp i omega_ pmatrix vspacemm Show that the function yt sinomega_ t is the solution for the initial conditions y quad textrmand quad dot y omega_
Solution:
The solution y_t is a superposition of the fundamental solutions: pmatrix y_t dot y_t pmatrix a_ vec v_ e^lambda_ t + a_ vec v_ e^lambda_ t For t we find y_ a_ -i+a_ i -i a_-a_ Longrightarrow a_ a_ dot y_ omega_ a_ omega_ + a_ omega_ omega_ a_+a_ Longrightarrow a_ + a_ a_ Longrightarrow a_ a_ frac It follows that y_t fracleft-i e^iomega_ t+i e^-iomega_ tright -fracilefte^iomega_ t-e^-iomega_ tright -fraci isinomega_ t -i^ sinomega_ t sinomega_ t
Contained in these collections: