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Spannung an Leiterschleife

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We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
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That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.

About difficulty...

We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.

That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:

Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise

Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise

Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise

Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise

Level 5 -
Level 6 -

Exercise

https://texercises.com/exercise/spannung-an-leiterschleife/

Question

Solution

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The following quantities appear in the problem: Länge \(\ell\) / elektrische Stromstärke \(I\) / Magnetische Flussdichte \(B\) / elektrische Spannung \(U\) / elektrischer Widerstand \(R\) / Fläche \(A\) / Radius \(r\) / Umfang \(u\) / spezifischer elektrischer Widerstand \(\rho\) /

The following formulas must be used to solve the exercise: \(u = 2\pi r \quad \) \(B = \dfrac{\mu_0 I}{2r} \quad \) \(U=RI \quad \) \(R = \varrho \dfrac{\ell}{A} \quad \)

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Exercise:
Im Zentrum eines zu einem Kreis mit dm Radius gebogenen Leiters mit millimetersquared Querschnitt misst man eine magnetische Flussdichte von nT. Mit welcher Spannung wird der Eisraht Formelbuch.microohmmeter versorgt?

Solution:
boxGegeben r dm .m A millimetersquared metersquared B nT T rho .microohmmeter .ohmmeter boxGesucht textSpannung Usivolt Um das angegebene Magnetfeld im Zentrum zu erzeugen muss die Stromstärke in dem Kreisstrom I fracrBmu_ .A betragen. Die Länge des Leiters ist ausserdem ell pi r .em womit sein Widerstand R rho fracellA .ohm ist. Die Spannung die anzulegen wäre beträgt also: U RI rho fracellA fracrBmu_ rho fracpi rA fracrBmu_ fracpi rho r^ Bmu_ A .V boxbox U fracpi rho r^ Bmu_ A .V .mV

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Attributes & Decorations

Branches	Magnetism
Tags	elektromagnetismus, flussdichte, kreis, kreisstrom, magnetfeld, magnetische, magnetismus, physik, spannung, stromstärke, widerstand
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Difficulty	(3, default)
Points	5 (default)
Language	(Deutsch)
Type	Calculative / Quantity
Creator	uz
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