Stromstärke an Kondensator
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
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Exercise:
Welche Stromstärke misst man in einem einzig aus einem an Wechselspannung Ueff f angeschlossenen Kondensator Co bestehen Schaltkreis in dem Moment wo die momentane Spannung ihren Effektivwert annimmt?
Solution:
Geg sscUeff Ueff f f rightarrow omega fC C Co C % GesStromstärkei siA % Der Scheitelwert der Spannung beträgt solqtyhatusqrtsscUeffsqrt*UeffnV al hat u hatuf sqrt Ueff hatu. Diesen Wert nimmt die Spannung zum Zeitpunkt solqtytfracomega arccosfracsqrt/fCn*acos/sqrts al t fracomega arccosfracsscUeffhat u fracomega arccosfracsscUeffhatuf tf fracfC arccosfracsqrt t an. % Der Blindwiderstand des Kondensators beträgt solqtyZfracomega C/fCn*Cnohm al Z Zf fracfC C Z. Der Scheitelwert des Stroms ist damit solqtyhatisqrt sscUeff omega Csqrt*Ueffn*fCn*CnA al hatimath frachat uZ frachatufZf hatif frachatuZ hati. Beim Kondensator ist der Strom zur Spannung phi_u - phi_i -fracpi phasenverschoben. Zum oben berechneten Zeitpunkt misst man deshalb eine Stromstärke von solqtyiTsqrtsscUeffomega C cosarccosfracsqrt-Deltaphihatin*cosfCn*tn-pi/A al i hatimath cosomega t - Deltaphi hatif cosomega tf - Deltaphi iTf hati cosfCt - fracpi iT approx iTII. % i iTf &approx iTII
Welche Stromstärke misst man in einem einzig aus einem an Wechselspannung Ueff f angeschlossenen Kondensator Co bestehen Schaltkreis in dem Moment wo die momentane Spannung ihren Effektivwert annimmt?
Solution:
Geg sscUeff Ueff f f rightarrow omega fC C Co C % GesStromstärkei siA % Der Scheitelwert der Spannung beträgt solqtyhatusqrtsscUeffsqrt*UeffnV al hat u hatuf sqrt Ueff hatu. Diesen Wert nimmt die Spannung zum Zeitpunkt solqtytfracomega arccosfracsqrt/fCn*acos/sqrts al t fracomega arccosfracsscUeffhat u fracomega arccosfracsscUeffhatuf tf fracfC arccosfracsqrt t an. % Der Blindwiderstand des Kondensators beträgt solqtyZfracomega C/fCn*Cnohm al Z Zf fracfC C Z. Der Scheitelwert des Stroms ist damit solqtyhatisqrt sscUeff omega Csqrt*Ueffn*fCn*CnA al hatimath frachat uZ frachatufZf hatif frachatuZ hati. Beim Kondensator ist der Strom zur Spannung phi_u - phi_i -fracpi phasenverschoben. Zum oben berechneten Zeitpunkt misst man deshalb eine Stromstärke von solqtyiTsqrtsscUeffomega C cosarccosfracsqrt-Deltaphihatin*cosfCn*tn-pi/A al i hatimath cosomega t - Deltaphi hatif cosomega tf - Deltaphi iTf hati cosfCt - fracpi iT approx iTII. % i iTf &approx iTII
Meta Information
Exercise:
Welche Stromstärke misst man in einem einzig aus einem an Wechselspannung Ueff f angeschlossenen Kondensator Co bestehen Schaltkreis in dem Moment wo die momentane Spannung ihren Effektivwert annimmt?
Solution:
Geg sscUeff Ueff f f rightarrow omega fC C Co C % GesStromstärkei siA % Der Scheitelwert der Spannung beträgt solqtyhatusqrtsscUeffsqrt*UeffnV al hat u hatuf sqrt Ueff hatu. Diesen Wert nimmt die Spannung zum Zeitpunkt solqtytfracomega arccosfracsqrt/fCn*acos/sqrts al t fracomega arccosfracsscUeffhat u fracomega arccosfracsscUeffhatuf tf fracfC arccosfracsqrt t an. % Der Blindwiderstand des Kondensators beträgt solqtyZfracomega C/fCn*Cnohm al Z Zf fracfC C Z. Der Scheitelwert des Stroms ist damit solqtyhatisqrt sscUeff omega Csqrt*Ueffn*fCn*CnA al hatimath frachat uZ frachatufZf hatif frachatuZ hati. Beim Kondensator ist der Strom zur Spannung phi_u - phi_i -fracpi phasenverschoben. Zum oben berechneten Zeitpunkt misst man deshalb eine Stromstärke von solqtyiTsqrtsscUeffomega C cosarccosfracsqrt-Deltaphihatin*cosfCn*tn-pi/A al i hatimath cosomega t - Deltaphi hatif cosomega tf - Deltaphi iTf hati cosfCt - fracpi iT approx iTII. % i iTf &approx iTII
Welche Stromstärke misst man in einem einzig aus einem an Wechselspannung Ueff f angeschlossenen Kondensator Co bestehen Schaltkreis in dem Moment wo die momentane Spannung ihren Effektivwert annimmt?
Solution:
Geg sscUeff Ueff f f rightarrow omega fC C Co C % GesStromstärkei siA % Der Scheitelwert der Spannung beträgt solqtyhatusqrtsscUeffsqrt*UeffnV al hat u hatuf sqrt Ueff hatu. Diesen Wert nimmt die Spannung zum Zeitpunkt solqtytfracomega arccosfracsqrt/fCn*acos/sqrts al t fracomega arccosfracsscUeffhat u fracomega arccosfracsscUeffhatuf tf fracfC arccosfracsqrt t an. % Der Blindwiderstand des Kondensators beträgt solqtyZfracomega C/fCn*Cnohm al Z Zf fracfC C Z. Der Scheitelwert des Stroms ist damit solqtyhatisqrt sscUeff omega Csqrt*Ueffn*fCn*CnA al hatimath frachat uZ frachatufZf hatif frachatuZ hati. Beim Kondensator ist der Strom zur Spannung phi_u - phi_i -fracpi phasenverschoben. Zum oben berechneten Zeitpunkt misst man deshalb eine Stromstärke von solqtyiTsqrtsscUeffomega C cosarccosfracsqrt-Deltaphihatin*cosfCn*tn-pi/A al i hatimath cosomega t - Deltaphi hatif cosomega tf - Deltaphi iTf hati cosfCt - fracpi iT approx iTII. % i iTf &approx iTII
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