Typical house driven by nuclear fusion
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
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Exercise:
If a typical house requires PO of electric power on average what minimum of deuterium fuel would have to be used in a year to supply these electrical needs? Ase the fusion reaction isotopeD+isotopeD rightarrow isotopeHe+mboxn. The mass of deuterium is mDO the mass of Helium- mHeO and the neutron has a mass of ncmnu.
Solution:
If we take the mass difference of the considered reaction we get Delta m sscmD - sscmHe - sscmn mD - mHe - ncmnu dmu dmk. According to Einstein's energy-mass-equivalence this corresponds to E_ Delta m c^ dmk qtyncc^ Ep EpM of energy which comes out of the reaction as kinetic energy i.e. velocity of the neutron. A typical house requires E Pt P t Eh EhM per year. The fusion reaction above hence needs to run N' fracEE_ fracEhEp N times. Each reaction requires two isotopeH atoms. Therefore N N' N Nz n nQ isotopeH atoms are required. They have a mass of m n M n M m mgQ.
If a typical house requires PO of electric power on average what minimum of deuterium fuel would have to be used in a year to supply these electrical needs? Ase the fusion reaction isotopeD+isotopeD rightarrow isotopeHe+mboxn. The mass of deuterium is mDO the mass of Helium- mHeO and the neutron has a mass of ncmnu.
Solution:
If we take the mass difference of the considered reaction we get Delta m sscmD - sscmHe - sscmn mD - mHe - ncmnu dmu dmk. According to Einstein's energy-mass-equivalence this corresponds to E_ Delta m c^ dmk qtyncc^ Ep EpM of energy which comes out of the reaction as kinetic energy i.e. velocity of the neutron. A typical house requires E Pt P t Eh EhM per year. The fusion reaction above hence needs to run N' fracEE_ fracEhEp N times. Each reaction requires two isotopeH atoms. Therefore N N' N Nz n nQ isotopeH atoms are required. They have a mass of m n M n M m mgQ.
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Exercise:
If a typical house requires PO of electric power on average what minimum of deuterium fuel would have to be used in a year to supply these electrical needs? Ase the fusion reaction isotopeD+isotopeD rightarrow isotopeHe+mboxn. The mass of deuterium is mDO the mass of Helium- mHeO and the neutron has a mass of ncmnu.
Solution:
If we take the mass difference of the considered reaction we get Delta m sscmD - sscmHe - sscmn mD - mHe - ncmnu dmu dmk. According to Einstein's energy-mass-equivalence this corresponds to E_ Delta m c^ dmk qtyncc^ Ep EpM of energy which comes out of the reaction as kinetic energy i.e. velocity of the neutron. A typical house requires E Pt P t Eh EhM per year. The fusion reaction above hence needs to run N' fracEE_ fracEhEp N times. Each reaction requires two isotopeH atoms. Therefore N N' N Nz n nQ isotopeH atoms are required. They have a mass of m n M n M m mgQ.
If a typical house requires PO of electric power on average what minimum of deuterium fuel would have to be used in a year to supply these electrical needs? Ase the fusion reaction isotopeD+isotopeD rightarrow isotopeHe+mboxn. The mass of deuterium is mDO the mass of Helium- mHeO and the neutron has a mass of ncmnu.
Solution:
If we take the mass difference of the considered reaction we get Delta m sscmD - sscmHe - sscmn mD - mHe - ncmnu dmu dmk. According to Einstein's energy-mass-equivalence this corresponds to E_ Delta m c^ dmk qtyncc^ Ep EpM of energy which comes out of the reaction as kinetic energy i.e. velocity of the neutron. A typical house requires E Pt P t Eh EhM per year. The fusion reaction above hence needs to run N' fracEE_ fracEhEp N times. Each reaction requires two isotopeH atoms. Therefore N N' N Nz n nQ isotopeH atoms are required. They have a mass of m n M n M m mgQ.
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Asked Quantity:
Masse \(m\)
in
Kilogramm \(\rm kg\)
Physical Quantity
Eigenschaft der Materie
Unit
Base?
SI?
Metric?
Coherent?
Imperial?