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The following quantities appear in the problem: Masse \(m\) / Temperatur \(T\) / Wärme \(Q\) / Wärmekapazität \(c\) /
The following formulas must be used to solve the exercise: \(Q = c \cdot m \cdot \Delta\vartheta \quad \)
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Exercise:
Wie viel würde sich die Temperatur von .g Wolfram cO ändern wenn man mJ Wärme entziehen würde?

Solution:
WaermeWolfram newqtym.kg newqtyQJ solqtyDTfracQcmQn/cWon/mncelsius al Deltatheta DTf fracQcWom DTTT
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Exercise:
Wie viel würde sich die Temperatur von .g Wolfram cO ändern wenn man mJ Wärme entziehen würde?

Solution:
WaermeWolfram newqtym.kg newqtyQJ solqtyDTfracQcmQn/cWon/mncelsius al Deltatheta DTf fracQcWom DTTT
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Attributes & Decorations
Tags
spezifische energie, wolfram, wärme
Difficulty
(1, default)
Points
2 (default)
Language
GER (Deutsch)
Type
Calculative / Quantity
Decoration
Content image