Zürichsee
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
Need help? Yes, please!
The following quantities appear in the problem:
Masse \(m\) / Volumen \(V\) / molare Masse \(M\) / Stoffmenge \(n\) / Radius \(r\) / Oberfläche \(S\) / Dichte \(\varrho\) / Anzahl \(N\) /
The following formulas must be used to solve the exercise:
\(\varrho = \dfrac{m}{V} \quad \) \(S = 4 \pi r^2 \quad \) \(m = nM \quad \) \(N = n \cdot N_{\rm A} \quad \)
No explanation / solution video for this exercise has yet been created.
But there is a video to a similar exercise:
In case your browser prevents YouTube embedding: https://youtu.be/7opQL8-cC0E
But there is a video to a similar exercise:
Exercise:
In einem Gedankenexperiment entimmt man dem Zürichsee von ca. pqkm^ Volumen einen Liter Wasser und markiert die so geschöpften Moleküle rot und giesst dann das Wasser in den See zurück. Die rot markierten Moleküle verteilen sich nun gleichmässig im See. Wie viele dieser Moleküle erhält man wieder wenn man zum zweitenmal einen Liter Wasser schöpft?
Solution:
Im Zürichsee hat es eine Wassermasse von m_mboxtiny See rho V pqkg/m^ pqem^ pqekg . Diese entspricht einer Anzahl chemicalH_O-Moleküle von n_mboxtiny See fracm_mboxtiny Seemmol fracpqekgpq.g/mol pq.emol . Eine analoge Rechnung zeigt dass in einem Liter Wasser pq.mol Moleküle sind. Damit ist im Mittel jedes fracpq.emolpq.mol numpr.emathrm-te Molekül ein markiertes glqq rotesgrqq Molekül. Da ein Liter weiterhin aus pq.mol Molekülen besteht finden wir rund frac. numpr.enumpr.e numpr.e markierte Moleküle in einem beliebigen Liter Wasser.
In einem Gedankenexperiment entimmt man dem Zürichsee von ca. pqkm^ Volumen einen Liter Wasser und markiert die so geschöpften Moleküle rot und giesst dann das Wasser in den See zurück. Die rot markierten Moleküle verteilen sich nun gleichmässig im See. Wie viele dieser Moleküle erhält man wieder wenn man zum zweitenmal einen Liter Wasser schöpft?
Solution:
Im Zürichsee hat es eine Wassermasse von m_mboxtiny See rho V pqkg/m^ pqem^ pqekg . Diese entspricht einer Anzahl chemicalH_O-Moleküle von n_mboxtiny See fracm_mboxtiny Seemmol fracpqekgpq.g/mol pq.emol . Eine analoge Rechnung zeigt dass in einem Liter Wasser pq.mol Moleküle sind. Damit ist im Mittel jedes fracpq.emolpq.mol numpr.emathrm-te Molekül ein markiertes glqq rotesgrqq Molekül. Da ein Liter weiterhin aus pq.mol Molekülen besteht finden wir rund frac. numpr.enumpr.e numpr.e markierte Moleküle in einem beliebigen Liter Wasser.
Meta Information
Exercise:
In einem Gedankenexperiment entimmt man dem Zürichsee von ca. pqkm^ Volumen einen Liter Wasser und markiert die so geschöpften Moleküle rot und giesst dann das Wasser in den See zurück. Die rot markierten Moleküle verteilen sich nun gleichmässig im See. Wie viele dieser Moleküle erhält man wieder wenn man zum zweitenmal einen Liter Wasser schöpft?
Solution:
Im Zürichsee hat es eine Wassermasse von m_mboxtiny See rho V pqkg/m^ pqem^ pqekg . Diese entspricht einer Anzahl chemicalH_O-Moleküle von n_mboxtiny See fracm_mboxtiny Seemmol fracpqekgpq.g/mol pq.emol . Eine analoge Rechnung zeigt dass in einem Liter Wasser pq.mol Moleküle sind. Damit ist im Mittel jedes fracpq.emolpq.mol numpr.emathrm-te Molekül ein markiertes glqq rotesgrqq Molekül. Da ein Liter weiterhin aus pq.mol Molekülen besteht finden wir rund frac. numpr.enumpr.e numpr.e markierte Moleküle in einem beliebigen Liter Wasser.
In einem Gedankenexperiment entimmt man dem Zürichsee von ca. pqkm^ Volumen einen Liter Wasser und markiert die so geschöpften Moleküle rot und giesst dann das Wasser in den See zurück. Die rot markierten Moleküle verteilen sich nun gleichmässig im See. Wie viele dieser Moleküle erhält man wieder wenn man zum zweitenmal einen Liter Wasser schöpft?
Solution:
Im Zürichsee hat es eine Wassermasse von m_mboxtiny See rho V pqkg/m^ pqem^ pqekg . Diese entspricht einer Anzahl chemicalH_O-Moleküle von n_mboxtiny See fracm_mboxtiny Seemmol fracpqekgpq.g/mol pq.emol . Eine analoge Rechnung zeigt dass in einem Liter Wasser pq.mol Moleküle sind. Damit ist im Mittel jedes fracpq.emolpq.mol numpr.emathrm-te Molekül ein markiertes glqq rotesgrqq Molekül. Da ein Liter weiterhin aus pq.mol Molekülen besteht finden wir rund frac. numpr.enumpr.e numpr.e markierte Moleküle in einem beliebigen Liter Wasser.
Contained in these collections
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Ozean by TeXercises
| Title | Matched on |
|---|---|
| Zürichsee | title |
| Bodensee | tags |
| Badewanne | tags |
| Badewanne | tags |
| Hydrogen atoms in a pound of water | tags |
Similar exercises (9)
| Title | Matched on |
|---|---|
| Zürichsee | title |
| Bodensee | tags |
| Badewanne | tags |
| Badewanne | tags |
| Hydrogen atoms in a pound of water | tags |
| Masse von Methanol-Molekülen | tags |
| Ethanol molecules | tags |
| Masse von Methanol-Molekülen | tags |
| Wassermoleküle | tags |