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Dichte von Venus

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That being said... How many "default points" should you associate with an exercise upon creation?
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But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.

About difficulty...

We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with

\LaTeX

-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.

That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:

Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise

Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise

Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise

Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise

Level 5 -
Level 6 -

Exercise

https://texercises.com/exercise/dichte-von-venus/

Question

Solution

Short

Video

\LaTeX

Need help? Yes, please!

The following quantities appear in the problem: Masse

m

/ Volumen

V

/ Ortsfaktor

g

/ Radius

r

/ Dichte

\varrho

The following formulas must be used to solve the exercise:

\varrho = \dfrac{m}{V} \quad

g = \dfrac{GM}{r^2} \quad

V = \dfrac{4}{3}\pi r^3 \quad

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Exercise:
Der kugelförmige Planet Venus hat ein Volumen von .ecubickilometer und die Fallbeschleunigung auf seiner Oberfläche beträgt .q. Berechne die mittlere Dichte von Venus.

Solution:
newqtyV.ecubicmeter newqtyg.q newqtyG.cubicmeterperkilogrampersecondsquared Geg V .ecubickilometer V g g GesMittlere Dichterhosikgpmk Der Radius von der Kugel Venus ist gemäss den Daten: solqtyrsqrtfracVpi*Vn/*pi**/m r rf leftfracVpiright^frac sqrtfrac .ecubicmeterpi r Die Masse von Venus ist: solqtymfracgr^Ggn*rn*rn/Gnkg m mf frac.q qtyr^G m Die mittlere Dichte von Venus ist also: solqtyrhfracmVmn/Vnkgpmk rho rhf fracfracgr^GV fracg leftleftfracVpiright^frac right^GV fracg leftfracVpiright^frac GV sqrtfracpi^ V fracgG fracmV rh rho sqrtfracpi^ V fracgG rh

Meta Information

$\LaTeX$ -Code

Contained in these collections:

Planet und Dichte by TeXercises

5 | 11
Aufgaben Kap. B4 by cm

14 | 20

Asked Quantity: Dichte

\varrho

in Kilogramm pro Kubikmeter

\rm \frac{kg}{m^3}

Attributes & Decorations

Branches	Gravitation
Tags	fallbeschleunigung, gravitation, gravitationsgesetz, physik, planet, venus
Content image
Difficulty	(3, default)
Points	5 (default)
Language	(Deutsch)
Type	Calculative / Quantity
Creator	uz
Decoration
File
Link