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https://texercises.com/exercise/hohe-eines-silberkegels/
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The following quantities appear in the problem: Masse \(m\) / Volumen \(V\) / Höhe \(h\) / Radius \(r\) / Dichte \(\varrho\) /
The following formulas must be used to solve the exercise: \(\varrho = \dfrac{m}{V} \quad \) \(V = \dfrac{1}{3}\pi r^2 h \quad \)
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Exercise:
Berechne die Höhe eines Silberkegels mit mO Masses falls dessen Grundfläche RO Radius hat. Die Dichte von Silber beträgt rund rO.

Solution:
Geg m mO m r RO R rho r r GesHöhehsim Der Silberkegel hat V fracmrho fracmr V Volumen womit er h fracVpi r^ fracfracmrhopi r^ fracmpi rho r^ frac Vpi qtyR^ h approx hS hP- hat. h fracmpi rho r^ hS hP-
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Exercise:
Berechne die Höhe eines Silberkegels mit mO Masses falls dessen Grundfläche RO Radius hat. Die Dichte von Silber beträgt rund rO.

Solution:
Geg m mO m r RO R rho r r GesHöhehsim Der Silberkegel hat V fracmrho fracmr V Volumen womit er h fracVpi r^ fracfracmrhopi r^ fracmpi rho r^ frac Vpi qtyR^ h approx hS hP- hat. h fracmpi rho r^ hS hP-
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Attributes & Decorations
Asked Quantity
Tags
dichte, höhe, kegel, mechanik, physik, silber, volume
Difficulty
(2, default)
Points
5 (default)
Language
GER (Deutsch)
Type
Calculative / Quantity
Decoration
Content image