Körper bestimmter Dichte an Schraubenfeder hängen
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
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Exercise:
Ein Körper mit VO Volumen und rO Dichte wird an eine Schraubenfeder gehängt die im unbelasteten Zustand saO lang ist. Bei Belastung Feder mit FO hat diese sbO Länge. Welche Verlängerung erfährt die Feder falls man an sie den beschriebenen Körper hängt?
Solution:
Geg V VO V rho rO r s_ saO sa F FO F s_ sbO sb GesVerlängerungDelta xsim Generell gilt das Federgesetz: F_mathrmFDDelta x Mit Kräftegleichgewicht gilt F_mathrmFsscFGm g und damit: m gDDelta xRa Delta xfracm gD Aus den Angaben zu Volumen und Dichte berechnen wir die Masse der Last: mvarrho Vsig.sikg Aus den Angaben zur Verlängerung der Feder bei einer Last von siN berechnen wir die Federkonstante: F_DDelta x_Ra DfracF_Delta x_siN/m Damit erhalten wir: Delta xfracm gDres.m
Ein Körper mit VO Volumen und rO Dichte wird an eine Schraubenfeder gehängt die im unbelasteten Zustand saO lang ist. Bei Belastung Feder mit FO hat diese sbO Länge. Welche Verlängerung erfährt die Feder falls man an sie den beschriebenen Körper hängt?
Solution:
Geg V VO V rho rO r s_ saO sa F FO F s_ sbO sb GesVerlängerungDelta xsim Generell gilt das Federgesetz: F_mathrmFDDelta x Mit Kräftegleichgewicht gilt F_mathrmFsscFGm g und damit: m gDDelta xRa Delta xfracm gD Aus den Angaben zu Volumen und Dichte berechnen wir die Masse der Last: mvarrho Vsig.sikg Aus den Angaben zur Verlängerung der Feder bei einer Last von siN berechnen wir die Federkonstante: F_DDelta x_Ra DfracF_Delta x_siN/m Damit erhalten wir: Delta xfracm gDres.m
Meta Information
Exercise:
Ein Körper mit VO Volumen und rO Dichte wird an eine Schraubenfeder gehängt die im unbelasteten Zustand saO lang ist. Bei Belastung Feder mit FO hat diese sbO Länge. Welche Verlängerung erfährt die Feder falls man an sie den beschriebenen Körper hängt?
Solution:
Geg V VO V rho rO r s_ saO sa F FO F s_ sbO sb GesVerlängerungDelta xsim Generell gilt das Federgesetz: F_mathrmFDDelta x Mit Kräftegleichgewicht gilt F_mathrmFsscFGm g und damit: m gDDelta xRa Delta xfracm gD Aus den Angaben zu Volumen und Dichte berechnen wir die Masse der Last: mvarrho Vsig.sikg Aus den Angaben zur Verlängerung der Feder bei einer Last von siN berechnen wir die Federkonstante: F_DDelta x_Ra DfracF_Delta x_siN/m Damit erhalten wir: Delta xfracm gDres.m
Ein Körper mit VO Volumen und rO Dichte wird an eine Schraubenfeder gehängt die im unbelasteten Zustand saO lang ist. Bei Belastung Feder mit FO hat diese sbO Länge. Welche Verlängerung erfährt die Feder falls man an sie den beschriebenen Körper hängt?
Solution:
Geg V VO V rho rO r s_ saO sa F FO F s_ sbO sb GesVerlängerungDelta xsim Generell gilt das Federgesetz: F_mathrmFDDelta x Mit Kräftegleichgewicht gilt F_mathrmFsscFGm g und damit: m gDDelta xRa Delta xfracm gD Aus den Angaben zu Volumen und Dichte berechnen wir die Masse der Last: mvarrho Vsig.sikg Aus den Angaben zur Verlängerung der Feder bei einer Last von siN berechnen wir die Federkonstante: F_DDelta x_Ra DfracF_Delta x_siN/m Damit erhalten wir: Delta xfracm gDres.m
Contained in these collections:
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Federgesetz by uz
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Federkraft by pw
Asked Quantity:
Strecke \(s\)
in
Meter \(\rm m\)
Physical Quantity
Strecke \(s\)
Länge eines Weges zwischen zwei Punkten
Unit
Der Meter ist dadurch definiert, dass der Lichtgeschwindigkeit im Vakuum \(c\) ein fester Wert zugewiesen wurde und die Sekunde (\(\rm s\)) ebenfalls über eine Naturkonstante, die Schwingungsfrequenz definiert ist.
Base?
SI?
Metric?
Coherent?
Imperial?