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Querschnitt eines kupfernen Rings

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Level 5 -
Level 6 -

Exercise

https://texercises.com/exercise/querschnitt-eines-kupfernen-rings/

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The following quantities appear in the problem: Länge \(\ell\) / elektrische Stromstärke \(I\) / Magnetische Flussdichte \(B\) / elektrische Spannung \(U\) / elektrischer Widerstand \(R\) / Fläche \(A\) / Radius \(r\) / spezifischer elektrischer Widerstand \(\rho\) /

The following formulas must be used to solve the exercise: \(B = \dfrac{\mu_0 I}{2r} \quad \) \(U=RI \quad \) \(R = \varrho \dfrac{\ell}{A} \quad \)

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Exercise:
Welchen Querschnitt hat ein kupferner Ring mit ro Radius in dessen Zentrum ein Magnetfeld von Bo entsteht wenn man U Spannung an ihm anlegt? Der spezifische Widerstand von Kupfer beträgt S.

Solution:
Geg r ro r B Bo B U U sscrhoel S % GesFlächeA sim^ % Die Stromstärke im Ring beträgt: solqtyIfrac r Bmu_*rn*Bn/ncmuonA al I If frac r Bncmuo I Der Widerstand des Ringes ist folglich: solqtyRfracmu_ U r BUn/Inohm al R fracUI fracUIf Rf fracUI R Daraus lässt sich die Querschnittfläche des Rings berechnen: solqtyAfracpisscrhoelr^Bmu_USn**pi*rn**rn*Bn/ncmuon*Unm^ al A fracsscrhoel ellR fracsscrhoel pi rRf fracsscrhoel pi r r Bmu_ U Af fracS pi rR A approx AI % A Af &approx AI

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Contained in these collections:

3g SJ 2021/22 Dritte Prüfung by pw

9 | 9
Magnetfeld Kreisstrom Ohm'sches Gesetz Widerstand Leiter by TeXercises

3 | 4

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Tags	elektromagnetismus, kreisstrom, kupfer, leiter, magnetfeld, physik, ring
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Difficulty	(3, default)
Points	5 (default)
Language	(Deutsch)
Type	Calculative / Quantity
Creator	uz
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