Rotierende Feder
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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Exercise:
Eine rotiere Achse stehe senkrecht auf einer horizontalen Scheibe und sei mit ihr fest verbunden. An dieser Achse werde eine Feder D N/m befestigt. An das äussere Ende der Feder werde eine Masse kg angebracht. Wie schnell v und omega rotiert die Scheibe falls die Masse reibungsfrei um centim von seiner Ruhelage ausgelenkt wird. In der Ruhelage liegt die Masse centim von der Drehachse entfernt.
Solution:
Die Bewegungsgleichung lautet: F_Res F_F ma_z Rightarrow DDelta x fracmv^r+Delta x momega^r+Delta x. Somit erhalten wir: eqnarray* v & sqrtfracDDelta xr+Delta xm approx .m/smm omega & sqrtfracDDelta xmr+Delta x approx .s^-. eqnarray*
Eine rotiere Achse stehe senkrecht auf einer horizontalen Scheibe und sei mit ihr fest verbunden. An dieser Achse werde eine Feder D N/m befestigt. An das äussere Ende der Feder werde eine Masse kg angebracht. Wie schnell v und omega rotiert die Scheibe falls die Masse reibungsfrei um centim von seiner Ruhelage ausgelenkt wird. In der Ruhelage liegt die Masse centim von der Drehachse entfernt.
Solution:
Die Bewegungsgleichung lautet: F_Res F_F ma_z Rightarrow DDelta x fracmv^r+Delta x momega^r+Delta x. Somit erhalten wir: eqnarray* v & sqrtfracDDelta xr+Delta xm approx .m/smm omega & sqrtfracDDelta xmr+Delta x approx .s^-. eqnarray*
Meta Information
Exercise:
Eine rotiere Achse stehe senkrecht auf einer horizontalen Scheibe und sei mit ihr fest verbunden. An dieser Achse werde eine Feder D N/m befestigt. An das äussere Ende der Feder werde eine Masse kg angebracht. Wie schnell v und omega rotiert die Scheibe falls die Masse reibungsfrei um centim von seiner Ruhelage ausgelenkt wird. In der Ruhelage liegt die Masse centim von der Drehachse entfernt.
Solution:
Die Bewegungsgleichung lautet: F_Res F_F ma_z Rightarrow DDelta x fracmv^r+Delta x momega^r+Delta x. Somit erhalten wir: eqnarray* v & sqrtfracDDelta xr+Delta xm approx .m/smm omega & sqrtfracDDelta xmr+Delta x approx .s^-. eqnarray*
Eine rotiere Achse stehe senkrecht auf einer horizontalen Scheibe und sei mit ihr fest verbunden. An dieser Achse werde eine Feder D N/m befestigt. An das äussere Ende der Feder werde eine Masse kg angebracht. Wie schnell v und omega rotiert die Scheibe falls die Masse reibungsfrei um centim von seiner Ruhelage ausgelenkt wird. In der Ruhelage liegt die Masse centim von der Drehachse entfernt.
Solution:
Die Bewegungsgleichung lautet: F_Res F_F ma_z Rightarrow DDelta x fracmv^r+Delta x momega^r+Delta x. Somit erhalten wir: eqnarray* v & sqrtfracDDelta xr+Delta xm approx .m/smm omega & sqrtfracDDelta xmr+Delta x approx .s^-. eqnarray*
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| Title | Matched on |
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| Milchkrug | tags |
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