Stossdämpfer
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
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Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
Die Karosserie eines Lastwagens ist .t schwer. Bei der Zuladung von .t wird die Federung zusammengedrückt und die Karosserie senkt sich um .cm. Beim Fahren führt die Karosserie harmonische Schwingungen aus. abcliste abc Wie gross ist die Schwingungsfrequenz bei der angegebenen Zuladung? abc Bei welcher Zuladung ist die Schwingungsfrequenz halb so gross wie bei a? abcliste
Solution:
newqtyMo.t newqtyMMon ekg newqtymo.t newqtymmon ekg newqtyyo.cm newqtyyyon m % Geg M Mo M m mo m y yo y % abclist abc GesFrequenzf_ siHz % Die Federkonstante dieser Feder beträgt solqtyDfracmgymn*ncgn/ynnewtonpermeter al D fracFy Df fracmncgy D. % Die Frequenz ist damit solqtyfefracpisqrtfracmgM+my/*pi*sqrtDn/Mn+mnHz al f_ fracomega_pi fracpisqrtfracDM+m fef fracpi sqrtfracDM+m fe % f_ fef feII abc GesMassem^primesikg % Wir können diese Teilaufgabe elegant mit einer Proportionalität lösen: solqtymdM+m*Mn+mnkg al m &sim fracf^ m_f_^ m_ f_^ m_ m_ fracf_^f_^ m_ mdf qtyM+m md. % Das ist die Gesamtmasse für diese Schwingungsdauer. Davon müssen wir noch die Masse der Karosserie abziehen: solqtymprM+mmdn-Mnkg al m^prime m_ - M mprf md - M mpr. m^prime mprf mprII abclist
Die Karosserie eines Lastwagens ist .t schwer. Bei der Zuladung von .t wird die Federung zusammengedrückt und die Karosserie senkt sich um .cm. Beim Fahren führt die Karosserie harmonische Schwingungen aus. abcliste abc Wie gross ist die Schwingungsfrequenz bei der angegebenen Zuladung? abc Bei welcher Zuladung ist die Schwingungsfrequenz halb so gross wie bei a? abcliste
Solution:
newqtyMo.t newqtyMMon ekg newqtymo.t newqtymmon ekg newqtyyo.cm newqtyyyon m % Geg M Mo M m mo m y yo y % abclist abc GesFrequenzf_ siHz % Die Federkonstante dieser Feder beträgt solqtyDfracmgymn*ncgn/ynnewtonpermeter al D fracFy Df fracmncgy D. % Die Frequenz ist damit solqtyfefracpisqrtfracmgM+my/*pi*sqrtDn/Mn+mnHz al f_ fracomega_pi fracpisqrtfracDM+m fef fracpi sqrtfracDM+m fe % f_ fef feII abc GesMassem^primesikg % Wir können diese Teilaufgabe elegant mit einer Proportionalität lösen: solqtymdM+m*Mn+mnkg al m &sim fracf^ m_f_^ m_ f_^ m_ m_ fracf_^f_^ m_ mdf qtyM+m md. % Das ist die Gesamtmasse für diese Schwingungsdauer. Davon müssen wir noch die Masse der Karosserie abziehen: solqtymprM+mmdn-Mnkg al m^prime m_ - M mprf md - M mpr. m^prime mprf mprII abclist
Meta Information
Exercise:
Die Karosserie eines Lastwagens ist .t schwer. Bei der Zuladung von .t wird die Federung zusammengedrückt und die Karosserie senkt sich um .cm. Beim Fahren führt die Karosserie harmonische Schwingungen aus. abcliste abc Wie gross ist die Schwingungsfrequenz bei der angegebenen Zuladung? abc Bei welcher Zuladung ist die Schwingungsfrequenz halb so gross wie bei a? abcliste
Solution:
newqtyMo.t newqtyMMon ekg newqtymo.t newqtymmon ekg newqtyyo.cm newqtyyyon m % Geg M Mo M m mo m y yo y % abclist abc GesFrequenzf_ siHz % Die Federkonstante dieser Feder beträgt solqtyDfracmgymn*ncgn/ynnewtonpermeter al D fracFy Df fracmncgy D. % Die Frequenz ist damit solqtyfefracpisqrtfracmgM+my/*pi*sqrtDn/Mn+mnHz al f_ fracomega_pi fracpisqrtfracDM+m fef fracpi sqrtfracDM+m fe % f_ fef feII abc GesMassem^primesikg % Wir können diese Teilaufgabe elegant mit einer Proportionalität lösen: solqtymdM+m*Mn+mnkg al m &sim fracf^ m_f_^ m_ f_^ m_ m_ fracf_^f_^ m_ mdf qtyM+m md. % Das ist die Gesamtmasse für diese Schwingungsdauer. Davon müssen wir noch die Masse der Karosserie abziehen: solqtymprM+mmdn-Mnkg al m^prime m_ - M mprf md - M mpr. m^prime mprf mprII abclist
Die Karosserie eines Lastwagens ist .t schwer. Bei der Zuladung von .t wird die Federung zusammengedrückt und die Karosserie senkt sich um .cm. Beim Fahren führt die Karosserie harmonische Schwingungen aus. abcliste abc Wie gross ist die Schwingungsfrequenz bei der angegebenen Zuladung? abc Bei welcher Zuladung ist die Schwingungsfrequenz halb so gross wie bei a? abcliste
Solution:
newqtyMo.t newqtyMMon ekg newqtymo.t newqtymmon ekg newqtyyo.cm newqtyyyon m % Geg M Mo M m mo m y yo y % abclist abc GesFrequenzf_ siHz % Die Federkonstante dieser Feder beträgt solqtyDfracmgymn*ncgn/ynnewtonpermeter al D fracFy Df fracmncgy D. % Die Frequenz ist damit solqtyfefracpisqrtfracmgM+my/*pi*sqrtDn/Mn+mnHz al f_ fracomega_pi fracpisqrtfracDM+m fef fracpi sqrtfracDM+m fe % f_ fef feII abc GesMassem^primesikg % Wir können diese Teilaufgabe elegant mit einer Proportionalität lösen: solqtymdM+m*Mn+mnkg al m &sim fracf^ m_f_^ m_ f_^ m_ m_ fracf_^f_^ m_ mdf qtyM+m md. % Das ist die Gesamtmasse für diese Schwingungsdauer. Davon müssen wir noch die Masse der Karosserie abziehen: solqtymprM+mmdn-Mnkg al m^prime m_ - M mprf md - M mpr. m^prime mprf mprII abclist
Contained in these collections:
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Pendel by aej
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Federpendel by pw
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Harmonische Schwingung 0 by uz