Tiefe der Erdgasblase
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
Need help? Yes, please!
The following quantities appear in the problem:
Volumen \(V\) / Druck \(p\) / Ortsfaktor \(g\) / Höhe \(h\) / Dichte \(\varrho\) /
The following formulas must be used to solve the exercise:
\(p_1V_1 = p_2V_2 \quad \) \(p = \varrho g h \quad \)
No explanation / solution video for this exercise has yet been created.
But there is a video to a similar exercise:
In case your browser prevents YouTube embedding: https://youtu.be/5At5IRB8ejg
But there is a video to a similar exercise:
Exercise:
Eine Erdgasblase von .cubiccentimeter Volumen löst sich aus dem Grund eines tiefen Sees. Der äussere Luftdruck beträgt .bar und die Temperatur des Sees wird als konstant angenommen. In welcher Tiefe hat sich die Erdgasblase gelöst wenn sie gerade unter der Oberfläche ein Volumen von .cubiccentimeter eingenommen hat?
Solution:
boxGegeben V_ .cubiccentimeter cubicmeter p_ .bar ePa V_ .cubiccentimeter .cubicmeter boxGesucht textTiefe/Höhe des Wasserspiegels hsimeter Der Druck am Seeboden muss p_ fracV_V_p_ frac.cubicmetercubicmeter ePa .ePa betragen haben damit die Erdgasblase dort das angegebene kleine Volumen hat. Da der Luftdruck daran einen Anteil von ePa hat muss der Druckanteil des Wassers p_w p_-p_ fracV_V_p_ - p_ .ePa - ePa .ePa Der See hat somit eine Tiefe von h fracp_wrho g fracp_-p_rho g fracfracV_V_p_-p_rho g .em das sind rund .m. boxbox h fracp_V_-p_V_rho g V_ .em .m
Eine Erdgasblase von .cubiccentimeter Volumen löst sich aus dem Grund eines tiefen Sees. Der äussere Luftdruck beträgt .bar und die Temperatur des Sees wird als konstant angenommen. In welcher Tiefe hat sich die Erdgasblase gelöst wenn sie gerade unter der Oberfläche ein Volumen von .cubiccentimeter eingenommen hat?
Solution:
boxGegeben V_ .cubiccentimeter cubicmeter p_ .bar ePa V_ .cubiccentimeter .cubicmeter boxGesucht textTiefe/Höhe des Wasserspiegels hsimeter Der Druck am Seeboden muss p_ fracV_V_p_ frac.cubicmetercubicmeter ePa .ePa betragen haben damit die Erdgasblase dort das angegebene kleine Volumen hat. Da der Luftdruck daran einen Anteil von ePa hat muss der Druckanteil des Wassers p_w p_-p_ fracV_V_p_ - p_ .ePa - ePa .ePa Der See hat somit eine Tiefe von h fracp_wrho g fracp_-p_rho g fracfracV_V_p_-p_rho g .em das sind rund .m. boxbox h fracp_V_-p_V_rho g V_ .em .m
Meta Information
Exercise:
Eine Erdgasblase von .cubiccentimeter Volumen löst sich aus dem Grund eines tiefen Sees. Der äussere Luftdruck beträgt .bar und die Temperatur des Sees wird als konstant angenommen. In welcher Tiefe hat sich die Erdgasblase gelöst wenn sie gerade unter der Oberfläche ein Volumen von .cubiccentimeter eingenommen hat?
Solution:
boxGegeben V_ .cubiccentimeter cubicmeter p_ .bar ePa V_ .cubiccentimeter .cubicmeter boxGesucht textTiefe/Höhe des Wasserspiegels hsimeter Der Druck am Seeboden muss p_ fracV_V_p_ frac.cubicmetercubicmeter ePa .ePa betragen haben damit die Erdgasblase dort das angegebene kleine Volumen hat. Da der Luftdruck daran einen Anteil von ePa hat muss der Druckanteil des Wassers p_w p_-p_ fracV_V_p_ - p_ .ePa - ePa .ePa Der See hat somit eine Tiefe von h fracp_wrho g fracp_-p_rho g fracfracV_V_p_-p_rho g .em das sind rund .m. boxbox h fracp_V_-p_V_rho g V_ .em .m
Eine Erdgasblase von .cubiccentimeter Volumen löst sich aus dem Grund eines tiefen Sees. Der äussere Luftdruck beträgt .bar und die Temperatur des Sees wird als konstant angenommen. In welcher Tiefe hat sich die Erdgasblase gelöst wenn sie gerade unter der Oberfläche ein Volumen von .cubiccentimeter eingenommen hat?
Solution:
boxGegeben V_ .cubiccentimeter cubicmeter p_ .bar ePa V_ .cubiccentimeter .cubicmeter boxGesucht textTiefe/Höhe des Wasserspiegels hsimeter Der Druck am Seeboden muss p_ fracV_V_p_ frac.cubicmetercubicmeter ePa .ePa betragen haben damit die Erdgasblase dort das angegebene kleine Volumen hat. Da der Luftdruck daran einen Anteil von ePa hat muss der Druckanteil des Wassers p_w p_-p_ fracV_V_p_ - p_ .ePa - ePa .ePa Der See hat somit eine Tiefe von h fracp_wrho g fracp_-p_rho g fracfracV_V_p_-p_rho g .em das sind rund .m. boxbox h fracp_V_-p_V_rho g V_ .em .m
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Boyle-Mariotte und Schweredruck by TeXercises
Asked Quantity:
Höhe \(h\)
in
Meter \(\rm m\)
Physical Quantity
lotrechter Abstand von Referenzfläche
Unit
Der Meter ist dadurch definiert, dass der Lichtgeschwindigkeit im Vakuum \(c\) ein fester Wert zugewiesen wurde und die Sekunde (\(\rm s\)) ebenfalls über eine Naturkonstante, die Schwingungsfrequenz definiert ist.
Base?
SI?
Metric?
Coherent?
Imperial?