Exercise
https://texercises.com/exercise/broken-shinbone/
Question
Solution
Short
Video
\(\LaTeX\)
Need help? Yes, please!
The following quantities appear in the problem:
The following formulas must be used to solve the exercise:
No explanation / solution video to this exercise has yet been created.

Visit our YouTube-Channel to see solutions to other exercises.
Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
In a passenger lift the rope breaks and the cabin then falls hO o the depths without braking. At the bottom of the lift shaft it is coming to a halt within tO. There is a person in the cabin mO. The cross-section of his tibia is approximately AO. Bones withstand a maximum pressure of pbO. Will the shinbone break? One feet is .cm one inch is .cm and a pound is roughly g.

Solution:
The cabin of the elevator hits the floor with SolQtyvsqrt*ncgX*hX v sqrtgh sqrt ncg h v velocity. Because the floor brings the cabin to a halt within tO the floor accelerates the cabin i.e. changes its velocity with SolQtyavX/tXq a fracvt fracsqrtght fracvt a. This means that SolQtyFmX*aXN F ma m fracsqrtght m a F force is acting on the man in the cabin. The pressure acting on the mans legs he is standing on both legs is SolQtypFX//AXPa p fracFA' fracfracsqrtghtA fracsqrtghtA fracF A p &approx pS pP pb In all likelihood the shinbone will break. p fracsqrtghtA pS pP
Report An Error
You are on texercises.com.
reCaptcha will only work on our main-domain \(\TeX\)ercises.com!
Meta Information
\(\LaTeX\)-Code
Exercise:
In a passenger lift the rope breaks and the cabin then falls hO o the depths without braking. At the bottom of the lift shaft it is coming to a halt within tO. There is a person in the cabin mO. The cross-section of his tibia is approximately AO. Bones withstand a maximum pressure of pbO. Will the shinbone break? One feet is .cm one inch is .cm and a pound is roughly g.

Solution:
The cabin of the elevator hits the floor with SolQtyvsqrt*ncgX*hX v sqrtgh sqrt ncg h v velocity. Because the floor brings the cabin to a halt within tO the floor accelerates the cabin i.e. changes its velocity with SolQtyavX/tXq a fracvt fracsqrtght fracvt a. This means that SolQtyFmX*aXN F ma m fracsqrtght m a F force is acting on the man in the cabin. The pressure acting on the mans legs he is standing on both legs is SolQtypFX//AXPa p fracFA' fracfracsqrtghtA fracsqrtghtA fracF A p &approx pS pP pb In all likelihood the shinbone will break. p fracsqrtghtA pS pP
Contained in these collections
  1. Personenlift by TeXercises
    2 | 2

Similar exercises (28)
Title Creator Matched on
Personenlift uz tags
Force moyenne sur une balle uz formula
Junge mit Ball uz tagsformula
Cold Steel Blasrohr uz formula
Kaffeetasse auf Armaturenbrett uz formula
more (23 more)
Attributes & Decorations
Asked Quantity
Tags
aktionsprinzip, beschleunigung, druck, freier fall, kraft, mechanik, newtonsche gesetze, physik
Difficulty
(3, default)
Points
4 (default)
Language
ENG (English)
Type
Calculative / Quantity
Decoration
Content image