Kirchhoff (einfach)
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
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Exercise:
Bestimmen Sie für die nachfolge Schaltung die Ströme I_ I_ und I_. center usetikzlibrarycircuits.ee.IEC tikzpicturecircuit ee IEC %% Schaltung % Aussenherum Gegenuhrzeigersinn draw fillblack to resistorinfo'R_ -; draw fillblack - to resistorinfo'R_ - circle .mm node belowyshift-mm b; draw - to batteryinfo'U'_ - to resistorinfo'R_ ; draw fillblack to batteryinfo'U_ to current directioninfo'I_ circle .mm node aboveyshiftmm a; draw to batteryinfoU_ to current direction'info'I_; % Mittlere Verbindung draw to current direction'info'I_ -; draw - to batteryinfo'U_ -. to resistorinfo'R_ - ; tikzpicture center Zahlenwerte: U_ V U_ V U_ V U'_ V R_ .ohm R_ .ohm R_ ohm und R_ ohm.
Solution:
Betrachten wir zuerst den Knoten bei a so erhalten wir folge Gleichung: -I_ + I_ + I_ . Nun die linke Masche welche wir im Gegenuhrzeigersinn durchlaufen: U_ - R_I_ - U_ - R_I_ wobei R_ R_+R_ ist. Nun betrachten wir die recht Masche und durchlaufen sie im Uhrzeigersinn: U_' +R_I_ - U_ -R_I_ wobei U_' U_ + U'_ ist. Durch das Lösen dieses Gleichungssystems erhalten wir die nummerischen Wert für die Ströme: I_ A I_ .A und I_ -.A.
Bestimmen Sie für die nachfolge Schaltung die Ströme I_ I_ und I_. center usetikzlibrarycircuits.ee.IEC tikzpicturecircuit ee IEC %% Schaltung % Aussenherum Gegenuhrzeigersinn draw fillblack to resistorinfo'R_ -; draw fillblack - to resistorinfo'R_ - circle .mm node belowyshift-mm b; draw - to batteryinfo'U'_ - to resistorinfo'R_ ; draw fillblack to batteryinfo'U_ to current directioninfo'I_ circle .mm node aboveyshiftmm a; draw to batteryinfoU_ to current direction'info'I_; % Mittlere Verbindung draw to current direction'info'I_ -; draw - to batteryinfo'U_ -. to resistorinfo'R_ - ; tikzpicture center Zahlenwerte: U_ V U_ V U_ V U'_ V R_ .ohm R_ .ohm R_ ohm und R_ ohm.
Solution:
Betrachten wir zuerst den Knoten bei a so erhalten wir folge Gleichung: -I_ + I_ + I_ . Nun die linke Masche welche wir im Gegenuhrzeigersinn durchlaufen: U_ - R_I_ - U_ - R_I_ wobei R_ R_+R_ ist. Nun betrachten wir die recht Masche und durchlaufen sie im Uhrzeigersinn: U_' +R_I_ - U_ -R_I_ wobei U_' U_ + U'_ ist. Durch das Lösen dieses Gleichungssystems erhalten wir die nummerischen Wert für die Ströme: I_ A I_ .A und I_ -.A.
Meta Information
Exercise:
Bestimmen Sie für die nachfolge Schaltung die Ströme I_ I_ und I_. center usetikzlibrarycircuits.ee.IEC tikzpicturecircuit ee IEC %% Schaltung % Aussenherum Gegenuhrzeigersinn draw fillblack to resistorinfo'R_ -; draw fillblack - to resistorinfo'R_ - circle .mm node belowyshift-mm b; draw - to batteryinfo'U'_ - to resistorinfo'R_ ; draw fillblack to batteryinfo'U_ to current directioninfo'I_ circle .mm node aboveyshiftmm a; draw to batteryinfoU_ to current direction'info'I_; % Mittlere Verbindung draw to current direction'info'I_ -; draw - to batteryinfo'U_ -. to resistorinfo'R_ - ; tikzpicture center Zahlenwerte: U_ V U_ V U_ V U'_ V R_ .ohm R_ .ohm R_ ohm und R_ ohm.
Solution:
Betrachten wir zuerst den Knoten bei a so erhalten wir folge Gleichung: -I_ + I_ + I_ . Nun die linke Masche welche wir im Gegenuhrzeigersinn durchlaufen: U_ - R_I_ - U_ - R_I_ wobei R_ R_+R_ ist. Nun betrachten wir die recht Masche und durchlaufen sie im Uhrzeigersinn: U_' +R_I_ - U_ -R_I_ wobei U_' U_ + U'_ ist. Durch das Lösen dieses Gleichungssystems erhalten wir die nummerischen Wert für die Ströme: I_ A I_ .A und I_ -.A.
Bestimmen Sie für die nachfolge Schaltung die Ströme I_ I_ und I_. center usetikzlibrarycircuits.ee.IEC tikzpicturecircuit ee IEC %% Schaltung % Aussenherum Gegenuhrzeigersinn draw fillblack to resistorinfo'R_ -; draw fillblack - to resistorinfo'R_ - circle .mm node belowyshift-mm b; draw - to batteryinfo'U'_ - to resistorinfo'R_ ; draw fillblack to batteryinfo'U_ to current directioninfo'I_ circle .mm node aboveyshiftmm a; draw to batteryinfoU_ to current direction'info'I_; % Mittlere Verbindung draw to current direction'info'I_ -; draw - to batteryinfo'U_ -. to resistorinfo'R_ - ; tikzpicture center Zahlenwerte: U_ V U_ V U_ V U'_ V R_ .ohm R_ .ohm R_ ohm und R_ ohm.
Solution:
Betrachten wir zuerst den Knoten bei a so erhalten wir folge Gleichung: -I_ + I_ + I_ . Nun die linke Masche welche wir im Gegenuhrzeigersinn durchlaufen: U_ - R_I_ - U_ - R_I_ wobei R_ R_+R_ ist. Nun betrachten wir die recht Masche und durchlaufen sie im Uhrzeigersinn: U_' +R_I_ - U_ -R_I_ wobei U_' U_ + U'_ ist. Durch das Lösen dieses Gleichungssystems erhalten wir die nummerischen Wert für die Ströme: I_ A I_ .A und I_ -.A.
Contained in these collections
| Title | Creator | Matched on |
|---|---|---|
| Kirchhoff I | cm | tags |
| Kirchhoff III | cm | tags |
| Kirchhoff II | cm | tags |
| Ersatzwiderstand | cm | tags |
| Potentialdifferenz | cm | tags |
Similar exercises (9)
| Title | Creator | Matched on |
|---|---|---|
| Kirchhoff I | cm | tags |
| Kirchhoff III | cm | tags |
| Kirchhoff II | cm | tags |
| Ersatzwiderstand | cm | tags |
| Potentialdifferenz | cm | tags |
| Kirchhoff mit Kapazität | cm | tags |
| Multiple Choice Spannung, Strom, Widerstand | rb | tags |
| Multiple Choice Spannung, Strom, Widerstand (4) | rb | tags |
| Spule an Gleichstromquelle | test | tags |

