Kirchhoff II
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
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Exercise:
Bestimmen Sie für das nachfolge Schaltschema die Ströme I_ I_ und I_. center tikzpicturescale. drawthick fillwhite rectangle ; drawthick -- ; drawfillblack circle .mm node belowyshift-mm b;; drawthick fillwhite -. rectangle node fns R_ .; drawthick fillwhite .-. rectangle node fns R_ ..; drawthick fillwhite rectangle ; drawfillblack circle .mm; drawfillblack circle .mm; drawfillblack circle .mm node aboveyshiftmm a; drawthick fillwhite . rectangle node fns R_ .; drawthick fillwhite . rectangle node fns R_ .; drawthick fillwhite . rectangle node fns R_ .; drawthick . -- .; drawthick . -- . node above U_; drawdrawwhitevery thick . -- .; drawthick -. -- .; drawthick .-node below U_ -- .; drawdrawwhitevery thick . -- .; drawthick .. -- ..; drawthick -- node above U_; drawdrawwhitevery thick . -- .; drawvery thick -latex -- node above I_; drawvery thick -latex -- node above I_; drawvery thick -latex . -- . node right I_; tikzpicture center Mit den Widerstände R_ ohm R_ ohm R_ ohm R_ ohm und R_ ohm und den Spannungen U_ V U_ V und U_ V.
Solution:
Zuerst vereinfachen wir das Schaltschema etwas. R_ und R_ sind in Serie geschaltet und haben den Wert: R_ ohm. R_ und R_ sind parallel geschaltet und haben den Wert: R_ .ohm. Da durch die Spannung U_ und U_ der gleiche Strom fliesst und sie in Serie geschaltet sind können sie vereinfacht werden: U_ V. Damit erhalten wir das neue vereinfache Schaltschema. center tikzpicturescale. drawthick fillwhite rectangle ; drawthick -- ; drawfillblack circle .mm node belowyshift-mm b;; drawthick fillwhite -. rectangle node R_ .; % drawthick fillwhite rectangle ; % drawthick fillwhite . rectangle node R_ .; drawthick fillwhite . rectangle node R_ .; drawthick fillwhite . rectangle node R_ .; drawthick . -- .; drawthick . -- . node above U_; drawfillblack circle .mm node aboveyshiftmm a; drawdrawwhitevery thick . -- .; % drawthick -. -- .; % drawthick .-node below U_ -- .; % drawdrawwhitevery thick . -- .; drawthick .. -- ..; drawthick -- node above U_; drawdrawwhitevery thick . -- .; drawvery thick -latex -- node above I_; drawvery thick -latex -- node above I_; drawvery thick -latex . -- . node right I_; tikzpicture center Damit erhalten wir die folgen Gleichungen: eqnarray* I_ & I_ + I_ U_ & I_R_ + I_R_ U_ & -I_R_ + I_R_ eqnarray* Löst man diese Gleichungen nach den Variablen auf erhält man: eqnarray* I_ & fracU_+U_fracR_R_R_+R_+fracR_R_R_ .A I_ & fracU_- I_R_-R_ -.A I_ & I_+I_ .A eqnarray*
Bestimmen Sie für das nachfolge Schaltschema die Ströme I_ I_ und I_. center tikzpicturescale. drawthick fillwhite rectangle ; drawthick -- ; drawfillblack circle .mm node belowyshift-mm b;; drawthick fillwhite -. rectangle node fns R_ .; drawthick fillwhite .-. rectangle node fns R_ ..; drawthick fillwhite rectangle ; drawfillblack circle .mm; drawfillblack circle .mm; drawfillblack circle .mm node aboveyshiftmm a; drawthick fillwhite . rectangle node fns R_ .; drawthick fillwhite . rectangle node fns R_ .; drawthick fillwhite . rectangle node fns R_ .; drawthick . -- .; drawthick . -- . node above U_; drawdrawwhitevery thick . -- .; drawthick -. -- .; drawthick .-node below U_ -- .; drawdrawwhitevery thick . -- .; drawthick .. -- ..; drawthick -- node above U_; drawdrawwhitevery thick . -- .; drawvery thick -latex -- node above I_; drawvery thick -latex -- node above I_; drawvery thick -latex . -- . node right I_; tikzpicture center Mit den Widerstände R_ ohm R_ ohm R_ ohm R_ ohm und R_ ohm und den Spannungen U_ V U_ V und U_ V.
Solution:
Zuerst vereinfachen wir das Schaltschema etwas. R_ und R_ sind in Serie geschaltet und haben den Wert: R_ ohm. R_ und R_ sind parallel geschaltet und haben den Wert: R_ .ohm. Da durch die Spannung U_ und U_ der gleiche Strom fliesst und sie in Serie geschaltet sind können sie vereinfacht werden: U_ V. Damit erhalten wir das neue vereinfache Schaltschema. center tikzpicturescale. drawthick fillwhite rectangle ; drawthick -- ; drawfillblack circle .mm node belowyshift-mm b;; drawthick fillwhite -. rectangle node R_ .; % drawthick fillwhite rectangle ; % drawthick fillwhite . rectangle node R_ .; drawthick fillwhite . rectangle node R_ .; drawthick fillwhite . rectangle node R_ .; drawthick . -- .; drawthick . -- . node above U_; drawfillblack circle .mm node aboveyshiftmm a; drawdrawwhitevery thick . -- .; % drawthick -. -- .; % drawthick .-node below U_ -- .; % drawdrawwhitevery thick . -- .; drawthick .. -- ..; drawthick -- node above U_; drawdrawwhitevery thick . -- .; drawvery thick -latex -- node above I_; drawvery thick -latex -- node above I_; drawvery thick -latex . -- . node right I_; tikzpicture center Damit erhalten wir die folgen Gleichungen: eqnarray* I_ & I_ + I_ U_ & I_R_ + I_R_ U_ & -I_R_ + I_R_ eqnarray* Löst man diese Gleichungen nach den Variablen auf erhält man: eqnarray* I_ & fracU_+U_fracR_R_R_+R_+fracR_R_R_ .A I_ & fracU_- I_R_-R_ -.A I_ & I_+I_ .A eqnarray*
Meta Information
Exercise:
Bestimmen Sie für das nachfolge Schaltschema die Ströme I_ I_ und I_. center tikzpicturescale. drawthick fillwhite rectangle ; drawthick -- ; drawfillblack circle .mm node belowyshift-mm b;; drawthick fillwhite -. rectangle node fns R_ .; drawthick fillwhite .-. rectangle node fns R_ ..; drawthick fillwhite rectangle ; drawfillblack circle .mm; drawfillblack circle .mm; drawfillblack circle .mm node aboveyshiftmm a; drawthick fillwhite . rectangle node fns R_ .; drawthick fillwhite . rectangle node fns R_ .; drawthick fillwhite . rectangle node fns R_ .; drawthick . -- .; drawthick . -- . node above U_; drawdrawwhitevery thick . -- .; drawthick -. -- .; drawthick .-node below U_ -- .; drawdrawwhitevery thick . -- .; drawthick .. -- ..; drawthick -- node above U_; drawdrawwhitevery thick . -- .; drawvery thick -latex -- node above I_; drawvery thick -latex -- node above I_; drawvery thick -latex . -- . node right I_; tikzpicture center Mit den Widerstände R_ ohm R_ ohm R_ ohm R_ ohm und R_ ohm und den Spannungen U_ V U_ V und U_ V.
Solution:
Zuerst vereinfachen wir das Schaltschema etwas. R_ und R_ sind in Serie geschaltet und haben den Wert: R_ ohm. R_ und R_ sind parallel geschaltet und haben den Wert: R_ .ohm. Da durch die Spannung U_ und U_ der gleiche Strom fliesst und sie in Serie geschaltet sind können sie vereinfacht werden: U_ V. Damit erhalten wir das neue vereinfache Schaltschema. center tikzpicturescale. drawthick fillwhite rectangle ; drawthick -- ; drawfillblack circle .mm node belowyshift-mm b;; drawthick fillwhite -. rectangle node R_ .; % drawthick fillwhite rectangle ; % drawthick fillwhite . rectangle node R_ .; drawthick fillwhite . rectangle node R_ .; drawthick fillwhite . rectangle node R_ .; drawthick . -- .; drawthick . -- . node above U_; drawfillblack circle .mm node aboveyshiftmm a; drawdrawwhitevery thick . -- .; % drawthick -. -- .; % drawthick .-node below U_ -- .; % drawdrawwhitevery thick . -- .; drawthick .. -- ..; drawthick -- node above U_; drawdrawwhitevery thick . -- .; drawvery thick -latex -- node above I_; drawvery thick -latex -- node above I_; drawvery thick -latex . -- . node right I_; tikzpicture center Damit erhalten wir die folgen Gleichungen: eqnarray* I_ & I_ + I_ U_ & I_R_ + I_R_ U_ & -I_R_ + I_R_ eqnarray* Löst man diese Gleichungen nach den Variablen auf erhält man: eqnarray* I_ & fracU_+U_fracR_R_R_+R_+fracR_R_R_ .A I_ & fracU_- I_R_-R_ -.A I_ & I_+I_ .A eqnarray*
Bestimmen Sie für das nachfolge Schaltschema die Ströme I_ I_ und I_. center tikzpicturescale. drawthick fillwhite rectangle ; drawthick -- ; drawfillblack circle .mm node belowyshift-mm b;; drawthick fillwhite -. rectangle node fns R_ .; drawthick fillwhite .-. rectangle node fns R_ ..; drawthick fillwhite rectangle ; drawfillblack circle .mm; drawfillblack circle .mm; drawfillblack circle .mm node aboveyshiftmm a; drawthick fillwhite . rectangle node fns R_ .; drawthick fillwhite . rectangle node fns R_ .; drawthick fillwhite . rectangle node fns R_ .; drawthick . -- .; drawthick . -- . node above U_; drawdrawwhitevery thick . -- .; drawthick -. -- .; drawthick .-node below U_ -- .; drawdrawwhitevery thick . -- .; drawthick .. -- ..; drawthick -- node above U_; drawdrawwhitevery thick . -- .; drawvery thick -latex -- node above I_; drawvery thick -latex -- node above I_; drawvery thick -latex . -- . node right I_; tikzpicture center Mit den Widerstände R_ ohm R_ ohm R_ ohm R_ ohm und R_ ohm und den Spannungen U_ V U_ V und U_ V.
Solution:
Zuerst vereinfachen wir das Schaltschema etwas. R_ und R_ sind in Serie geschaltet und haben den Wert: R_ ohm. R_ und R_ sind parallel geschaltet und haben den Wert: R_ .ohm. Da durch die Spannung U_ und U_ der gleiche Strom fliesst und sie in Serie geschaltet sind können sie vereinfacht werden: U_ V. Damit erhalten wir das neue vereinfache Schaltschema. center tikzpicturescale. drawthick fillwhite rectangle ; drawthick -- ; drawfillblack circle .mm node belowyshift-mm b;; drawthick fillwhite -. rectangle node R_ .; % drawthick fillwhite rectangle ; % drawthick fillwhite . rectangle node R_ .; drawthick fillwhite . rectangle node R_ .; drawthick fillwhite . rectangle node R_ .; drawthick . -- .; drawthick . -- . node above U_; drawfillblack circle .mm node aboveyshiftmm a; drawdrawwhitevery thick . -- .; % drawthick -. -- .; % drawthick .-node below U_ -- .; % drawdrawwhitevery thick . -- .; drawthick .. -- ..; drawthick -- node above U_; drawdrawwhitevery thick . -- .; drawvery thick -latex -- node above I_; drawvery thick -latex -- node above I_; drawvery thick -latex . -- . node right I_; tikzpicture center Damit erhalten wir die folgen Gleichungen: eqnarray* I_ & I_ + I_ U_ & I_R_ + I_R_ U_ & -I_R_ + I_R_ eqnarray* Löst man diese Gleichungen nach den Variablen auf erhält man: eqnarray* I_ & fracU_+U_fracR_R_R_+R_+fracR_R_R_ .A I_ & fracU_- I_R_-R_ -.A I_ & I_+I_ .A eqnarray*
Contained in these collections
| Title | Creator | Matched on |
|---|---|---|
| Potentialdifferenz | cm | tags |
| Kirchhoff I | cm | tagstitle |
| Kirchhoff III | cm | tagstitle |
| Kirchhoff mit Kapazität | cm | tags |
| Multiple Choice | cm | tags |
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