Rausziehen
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
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Exercise:
Eine wie grosse Kraft F wird in der Abbildung benötigt um den Quader der Masse m_ kg mit einer Beschleunigung von a .^ herauszuziehen m_ kg wenn der Reibungskoeffizient zwischen all den Oberflächen mu . ist? center tikzpicturescale.erface/.style postactiondrawdecoratedecorationborderangle amplitude.cmsegment length.mm drawline widthpt -- -- ; drawthick rectangle nodexshift-.cmyshift-.cm m_; drawvery thick- -- nodeabove vec F; drawthick rectangle nodexshift-.cmyshift-.cm m_; drawvery thick . circle . cm; drawvery thick .. -- . .; drawvery thick . circle . cm; drawvery thick -.. -- -. .; drawblackline width.pterface..--..; drawline width.pt .. -- .. -- .. -- ..; tikzpicture center
Solution:
Da die Masse über die Schnur mit der Wand fest verbunden ist wird sie sich nicht bewegen damit gilt: F_N F_gquadtextundquad F_S F_R mu F_N mu F_g. Für die Masse zwei gilt: eqnarray* F_res^y & F_N - F_N - F_g F_res^x & F - F_R-F_R m_a eqnarray* Nachdem man alles in die letzte Gleichung eingesetzt hat bekommt man F mu gm_+m_+m_a approx N.
Eine wie grosse Kraft F wird in der Abbildung benötigt um den Quader der Masse m_ kg mit einer Beschleunigung von a .^ herauszuziehen m_ kg wenn der Reibungskoeffizient zwischen all den Oberflächen mu . ist? center tikzpicturescale.erface/.style postactiondrawdecoratedecorationborderangle amplitude.cmsegment length.mm drawline widthpt -- -- ; drawthick rectangle nodexshift-.cmyshift-.cm m_; drawvery thick- -- nodeabove vec F; drawthick rectangle nodexshift-.cmyshift-.cm m_; drawvery thick . circle . cm; drawvery thick .. -- . .; drawvery thick . circle . cm; drawvery thick -.. -- -. .; drawblackline width.pterface..--..; drawline width.pt .. -- .. -- .. -- ..; tikzpicture center
Solution:
Da die Masse über die Schnur mit der Wand fest verbunden ist wird sie sich nicht bewegen damit gilt: F_N F_gquadtextundquad F_S F_R mu F_N mu F_g. Für die Masse zwei gilt: eqnarray* F_res^y & F_N - F_N - F_g F_res^x & F - F_R-F_R m_a eqnarray* Nachdem man alles in die letzte Gleichung eingesetzt hat bekommt man F mu gm_+m_+m_a approx N.
Meta Information
Exercise:
Eine wie grosse Kraft F wird in der Abbildung benötigt um den Quader der Masse m_ kg mit einer Beschleunigung von a .^ herauszuziehen m_ kg wenn der Reibungskoeffizient zwischen all den Oberflächen mu . ist? center tikzpicturescale.erface/.style postactiondrawdecoratedecorationborderangle amplitude.cmsegment length.mm drawline widthpt -- -- ; drawthick rectangle nodexshift-.cmyshift-.cm m_; drawvery thick- -- nodeabove vec F; drawthick rectangle nodexshift-.cmyshift-.cm m_; drawvery thick . circle . cm; drawvery thick .. -- . .; drawvery thick . circle . cm; drawvery thick -.. -- -. .; drawblackline width.pterface..--..; drawline width.pt .. -- .. -- .. -- ..; tikzpicture center
Solution:
Da die Masse über die Schnur mit der Wand fest verbunden ist wird sie sich nicht bewegen damit gilt: F_N F_gquadtextundquad F_S F_R mu F_N mu F_g. Für die Masse zwei gilt: eqnarray* F_res^y & F_N - F_N - F_g F_res^x & F - F_R-F_R m_a eqnarray* Nachdem man alles in die letzte Gleichung eingesetzt hat bekommt man F mu gm_+m_+m_a approx N.
Eine wie grosse Kraft F wird in der Abbildung benötigt um den Quader der Masse m_ kg mit einer Beschleunigung von a .^ herauszuziehen m_ kg wenn der Reibungskoeffizient zwischen all den Oberflächen mu . ist? center tikzpicturescale.erface/.style postactiondrawdecoratedecorationborderangle amplitude.cmsegment length.mm drawline widthpt -- -- ; drawthick rectangle nodexshift-.cmyshift-.cm m_; drawvery thick- -- nodeabove vec F; drawthick rectangle nodexshift-.cmyshift-.cm m_; drawvery thick . circle . cm; drawvery thick .. -- . .; drawvery thick . circle . cm; drawvery thick -.. -- -. .; drawblackline width.pterface..--..; drawline width.pt .. -- .. -- .. -- ..; tikzpicture center
Solution:
Da die Masse über die Schnur mit der Wand fest verbunden ist wird sie sich nicht bewegen damit gilt: F_N F_gquadtextundquad F_S F_R mu F_N mu F_g. Für die Masse zwei gilt: eqnarray* F_res^y & F_N - F_N - F_g F_res^x & F - F_R-F_R m_a eqnarray* Nachdem man alles in die letzte Gleichung eingesetzt hat bekommt man F mu gm_+m_+m_a approx N.
Contained in these collections
| Title | Matched on |
|---|---|
| Blöcke stapeln | tags |
| Beizentrick | tags |
| Wagen rollt runter | tags |
| Schiefes Gleiten | tags |
| Reibende Kiste | tags |
Similar exercises (16)
| Title | Matched on |
|---|---|
| Blöcke stapeln | tags |
| Beizentrick | tags |
| Wagen rollt runter | tags |
| Schiefes Gleiten | tags |
| Reibende Kiste | tags |
| Hochschieben | tags |
| Schwebende beschleunigte Masse | tags |
| Korrigieren und Verbessern | tags |
| Rutschen | tags |
| Gleiten längs schiefer Ebene | tags |
| Beschleunigende Kraft | tags |
| Negative Beschleunigung | tags |
| Kraft zwischen zwei beschleunigten Wagen | tags |
| Hammer und Nagel | tags |
| Kraft und Beschleunigung | tags |
| Masse und Beschleunigung | tags |