Wassertopf
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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Video
\(\LaTeX\)
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Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
Ein Topf ist bis zur Höhe x_ mit Wasser gefüllt. in welcher Höhe h ist ein Loch zu bohren damit der austrete Wasserstrahl möglichst weit kommt?
Solution:
Die Zeit welche der Wasserstrahl zum Durchfallen der Höhe h benötigt ist t sqrtfrachg. Der hydrostatische Druck in der Höhe x_-h ist p rho g x_-h. Mit der Bernoulli-Gleichung p_ + frac rho v_^ p_ +frac rho v_^ findet man als Ausströmungsgeschwindigkeit: rho g x_-h frac rho v^ v sqrtgx_-h Damit gilt für die Weite des Wasserstrahls s vt sqrtgx_-h sqrtfrachg sqrthx_-h. Diese Weite soll maximal sein; dann muss auch s^ maximal sein was die Sache etwas erleichtert. Das Maximum von hx_-h^ ist dort wo die Ableitung nach h verschwindet also x_-h. Damit ist die Höhe h frac x_.
Ein Topf ist bis zur Höhe x_ mit Wasser gefüllt. in welcher Höhe h ist ein Loch zu bohren damit der austrete Wasserstrahl möglichst weit kommt?
Solution:
Die Zeit welche der Wasserstrahl zum Durchfallen der Höhe h benötigt ist t sqrtfrachg. Der hydrostatische Druck in der Höhe x_-h ist p rho g x_-h. Mit der Bernoulli-Gleichung p_ + frac rho v_^ p_ +frac rho v_^ findet man als Ausströmungsgeschwindigkeit: rho g x_-h frac rho v^ v sqrtgx_-h Damit gilt für die Weite des Wasserstrahls s vt sqrtgx_-h sqrtfrachg sqrthx_-h. Diese Weite soll maximal sein; dann muss auch s^ maximal sein was die Sache etwas erleichtert. Das Maximum von hx_-h^ ist dort wo die Ableitung nach h verschwindet also x_-h. Damit ist die Höhe h frac x_.
Meta Information
Exercise:
Ein Topf ist bis zur Höhe x_ mit Wasser gefüllt. in welcher Höhe h ist ein Loch zu bohren damit der austrete Wasserstrahl möglichst weit kommt?
Solution:
Die Zeit welche der Wasserstrahl zum Durchfallen der Höhe h benötigt ist t sqrtfrachg. Der hydrostatische Druck in der Höhe x_-h ist p rho g x_-h. Mit der Bernoulli-Gleichung p_ + frac rho v_^ p_ +frac rho v_^ findet man als Ausströmungsgeschwindigkeit: rho g x_-h frac rho v^ v sqrtgx_-h Damit gilt für die Weite des Wasserstrahls s vt sqrtgx_-h sqrtfrachg sqrthx_-h. Diese Weite soll maximal sein; dann muss auch s^ maximal sein was die Sache etwas erleichtert. Das Maximum von hx_-h^ ist dort wo die Ableitung nach h verschwindet also x_-h. Damit ist die Höhe h frac x_.
Ein Topf ist bis zur Höhe x_ mit Wasser gefüllt. in welcher Höhe h ist ein Loch zu bohren damit der austrete Wasserstrahl möglichst weit kommt?
Solution:
Die Zeit welche der Wasserstrahl zum Durchfallen der Höhe h benötigt ist t sqrtfrachg. Der hydrostatische Druck in der Höhe x_-h ist p rho g x_-h. Mit der Bernoulli-Gleichung p_ + frac rho v_^ p_ +frac rho v_^ findet man als Ausströmungsgeschwindigkeit: rho g x_-h frac rho v^ v sqrtgx_-h Damit gilt für die Weite des Wasserstrahls s vt sqrtgx_-h sqrtfrachg sqrthx_-h. Diese Weite soll maximal sein; dann muss auch s^ maximal sein was die Sache etwas erleichtert. Das Maximum von hx_-h^ ist dort wo die Ableitung nach h verschwindet also x_-h. Damit ist die Höhe h frac x_.
Contained in these collections:
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ETH 1. Vordiplom Physik Herbst 1993 by TeXercises
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Horizontaler Wurf und Bernoulli by TeXercises
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Horizontaler Wurf by uz