Schiefe Feder
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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Video
\(\LaTeX\)
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Exercise:
Das System in der Abbildung ist im Gleichgewicht. Wie stark wird die Feder eingedrückt? Zeigen Sie dass die Feder um x fracmgDbigsinalpha - mu_H+cosalphabigzusammen gedrückt wird falls die Haftreibungskonstante mu_H die Federkonstante D die Massen beide m sind und der Winkel in der schiefen Ebene alpha sind. center tikzpicturescale. % Massen draw fillgray! rectangle node m ..; draw .. -- .; draw fillgray!rotate around-: rectangle node m ..; draw .. -- ..; % Ebene draw very thick -- -- -- ; % Rolle draw thick fillgray! . circle .cm; draw fillblack . circle .cm; draw very thick -- .; % Feder draw thick -- ..; draw thick .. -- ..; draw decoratedecorationcoilsegment length.cmdrawblack .. -- node rightyshift.mm D ..; draw .. -- ..; % Winkel draw thick arc ::; node at .. alpha; tikzpicture center
Solution:
Für die horizontalliege Masse gilt: F_R_ F_S quad textund quad F_g_ F_N_. Daraus folgt dass F_S mu mg ist. Für die schiefe Masse gilt: F_g_ sinalpha F_S + F_R_ + F_F quad textund quad F_g_ cosalpha F_N_. Somit ist F_F F_g_ sinalpha- F_S - F_R_. Setzten wir alles ein erhalten wir: Dx mgsinalpha - mu mg - mu mg cosalpha. und daraus folgt was zu zeigen war.
Das System in der Abbildung ist im Gleichgewicht. Wie stark wird die Feder eingedrückt? Zeigen Sie dass die Feder um x fracmgDbigsinalpha - mu_H+cosalphabigzusammen gedrückt wird falls die Haftreibungskonstante mu_H die Federkonstante D die Massen beide m sind und der Winkel in der schiefen Ebene alpha sind. center tikzpicturescale. % Massen draw fillgray! rectangle node m ..; draw .. -- .; draw fillgray!rotate around-: rectangle node m ..; draw .. -- ..; % Ebene draw very thick -- -- -- ; % Rolle draw thick fillgray! . circle .cm; draw fillblack . circle .cm; draw very thick -- .; % Feder draw thick -- ..; draw thick .. -- ..; draw decoratedecorationcoilsegment length.cmdrawblack .. -- node rightyshift.mm D ..; draw .. -- ..; % Winkel draw thick arc ::; node at .. alpha; tikzpicture center
Solution:
Für die horizontalliege Masse gilt: F_R_ F_S quad textund quad F_g_ F_N_. Daraus folgt dass F_S mu mg ist. Für die schiefe Masse gilt: F_g_ sinalpha F_S + F_R_ + F_F quad textund quad F_g_ cosalpha F_N_. Somit ist F_F F_g_ sinalpha- F_S - F_R_. Setzten wir alles ein erhalten wir: Dx mgsinalpha - mu mg - mu mg cosalpha. und daraus folgt was zu zeigen war.
Meta Information
Exercise:
Das System in der Abbildung ist im Gleichgewicht. Wie stark wird die Feder eingedrückt? Zeigen Sie dass die Feder um x fracmgDbigsinalpha - mu_H+cosalphabigzusammen gedrückt wird falls die Haftreibungskonstante mu_H die Federkonstante D die Massen beide m sind und der Winkel in der schiefen Ebene alpha sind. center tikzpicturescale. % Massen draw fillgray! rectangle node m ..; draw .. -- .; draw fillgray!rotate around-: rectangle node m ..; draw .. -- ..; % Ebene draw very thick -- -- -- ; % Rolle draw thick fillgray! . circle .cm; draw fillblack . circle .cm; draw very thick -- .; % Feder draw thick -- ..; draw thick .. -- ..; draw decoratedecorationcoilsegment length.cmdrawblack .. -- node rightyshift.mm D ..; draw .. -- ..; % Winkel draw thick arc ::; node at .. alpha; tikzpicture center
Solution:
Für die horizontalliege Masse gilt: F_R_ F_S quad textund quad F_g_ F_N_. Daraus folgt dass F_S mu mg ist. Für die schiefe Masse gilt: F_g_ sinalpha F_S + F_R_ + F_F quad textund quad F_g_ cosalpha F_N_. Somit ist F_F F_g_ sinalpha- F_S - F_R_. Setzten wir alles ein erhalten wir: Dx mgsinalpha - mu mg - mu mg cosalpha. und daraus folgt was zu zeigen war.
Das System in der Abbildung ist im Gleichgewicht. Wie stark wird die Feder eingedrückt? Zeigen Sie dass die Feder um x fracmgDbigsinalpha - mu_H+cosalphabigzusammen gedrückt wird falls die Haftreibungskonstante mu_H die Federkonstante D die Massen beide m sind und der Winkel in der schiefen Ebene alpha sind. center tikzpicturescale. % Massen draw fillgray! rectangle node m ..; draw .. -- .; draw fillgray!rotate around-: rectangle node m ..; draw .. -- ..; % Ebene draw very thick -- -- -- ; % Rolle draw thick fillgray! . circle .cm; draw fillblack . circle .cm; draw very thick -- .; % Feder draw thick -- ..; draw thick .. -- ..; draw decoratedecorationcoilsegment length.cmdrawblack .. -- node rightyshift.mm D ..; draw .. -- ..; % Winkel draw thick arc ::; node at .. alpha; tikzpicture center
Solution:
Für die horizontalliege Masse gilt: F_R_ F_S quad textund quad F_g_ F_N_. Daraus folgt dass F_S mu mg ist. Für die schiefe Masse gilt: F_g_ sinalpha F_S + F_R_ + F_F quad textund quad F_g_ cosalpha F_N_. Somit ist F_F F_g_ sinalpha- F_S - F_R_. Setzten wir alles ein erhalten wir: Dx mgsinalpha - mu mg - mu mg cosalpha. und daraus folgt was zu zeigen war.
Contained in these collections
| Title | Matched on |
|---|---|
| Halten einer Kiste | tags |
| Körper ziehen | tags |
| Kleines Kind | tags |
| Realer freier Fall | tags |
| Gespannte Feder | tags |
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