Falsche und richtige Lösung
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
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Exercise:
Zeigen Sie ... enumerate item dass die Wellenfunktion Psixt Ae^kx-omega t die zeitabhängige Schrödinger-Gleichung nicht erfüllt. item dass die Wellenfunktion Psixt Ae^ikx-omega t die zeitabhängige Schrödinger-Gleichung erfüllt. enumerate Die zeitabhängige Schrödinger-Gleichung lautet: -frachbar^m fracpartial^partial x^Psixt + VxtPsixt ihbarfracpartial partial tPsixt.
Solution:
enumerate item Bestimmen wir die partiellen Ableitungen: eqnarray* fracpartial^ Psipartial x^ & k^ Psi fracpartial Psipartial t & -omega Psi eqnarray* Eingesetzt in die Gleichung erhalten wir: -hbar^k^Psi/m + VPsi -ihbaromegaPsi. Die rechte Seite dieser Gleichung ist rein imaginär die linke dagegen nicht. item analog dazu: eqnarray* fracpartial^ Psipartial x^ & -k^ Psi fracpartial Psipartial t & -iomega Psi eqnarray* Eingesetzt in die Gleichung erhalten wir: frachbar^k^mPsi + VPsi hbaromegaPsi. Das ist eine Lösung wenn hbaromega hbar^k^/m + V und dies entspricht der Energieerhaltung: E fracp^m + V wobei E hbar omega und p hbar k ist. enumerate
Zeigen Sie ... enumerate item dass die Wellenfunktion Psixt Ae^kx-omega t die zeitabhängige Schrödinger-Gleichung nicht erfüllt. item dass die Wellenfunktion Psixt Ae^ikx-omega t die zeitabhängige Schrödinger-Gleichung erfüllt. enumerate Die zeitabhängige Schrödinger-Gleichung lautet: -frachbar^m fracpartial^partial x^Psixt + VxtPsixt ihbarfracpartial partial tPsixt.
Solution:
enumerate item Bestimmen wir die partiellen Ableitungen: eqnarray* fracpartial^ Psipartial x^ & k^ Psi fracpartial Psipartial t & -omega Psi eqnarray* Eingesetzt in die Gleichung erhalten wir: -hbar^k^Psi/m + VPsi -ihbaromegaPsi. Die rechte Seite dieser Gleichung ist rein imaginär die linke dagegen nicht. item analog dazu: eqnarray* fracpartial^ Psipartial x^ & -k^ Psi fracpartial Psipartial t & -iomega Psi eqnarray* Eingesetzt in die Gleichung erhalten wir: frachbar^k^mPsi + VPsi hbaromegaPsi. Das ist eine Lösung wenn hbaromega hbar^k^/m + V und dies entspricht der Energieerhaltung: E fracp^m + V wobei E hbar omega und p hbar k ist. enumerate
Meta Information
Exercise:
Zeigen Sie ... enumerate item dass die Wellenfunktion Psixt Ae^kx-omega t die zeitabhängige Schrödinger-Gleichung nicht erfüllt. item dass die Wellenfunktion Psixt Ae^ikx-omega t die zeitabhängige Schrödinger-Gleichung erfüllt. enumerate Die zeitabhängige Schrödinger-Gleichung lautet: -frachbar^m fracpartial^partial x^Psixt + VxtPsixt ihbarfracpartial partial tPsixt.
Solution:
enumerate item Bestimmen wir die partiellen Ableitungen: eqnarray* fracpartial^ Psipartial x^ & k^ Psi fracpartial Psipartial t & -omega Psi eqnarray* Eingesetzt in die Gleichung erhalten wir: -hbar^k^Psi/m + VPsi -ihbaromegaPsi. Die rechte Seite dieser Gleichung ist rein imaginär die linke dagegen nicht. item analog dazu: eqnarray* fracpartial^ Psipartial x^ & -k^ Psi fracpartial Psipartial t & -iomega Psi eqnarray* Eingesetzt in die Gleichung erhalten wir: frachbar^k^mPsi + VPsi hbaromegaPsi. Das ist eine Lösung wenn hbaromega hbar^k^/m + V und dies entspricht der Energieerhaltung: E fracp^m + V wobei E hbar omega und p hbar k ist. enumerate
Zeigen Sie ... enumerate item dass die Wellenfunktion Psixt Ae^kx-omega t die zeitabhängige Schrödinger-Gleichung nicht erfüllt. item dass die Wellenfunktion Psixt Ae^ikx-omega t die zeitabhängige Schrödinger-Gleichung erfüllt. enumerate Die zeitabhängige Schrödinger-Gleichung lautet: -frachbar^m fracpartial^partial x^Psixt + VxtPsixt ihbarfracpartial partial tPsixt.
Solution:
enumerate item Bestimmen wir die partiellen Ableitungen: eqnarray* fracpartial^ Psipartial x^ & k^ Psi fracpartial Psipartial t & -omega Psi eqnarray* Eingesetzt in die Gleichung erhalten wir: -hbar^k^Psi/m + VPsi -ihbaromegaPsi. Die rechte Seite dieser Gleichung ist rein imaginär die linke dagegen nicht. item analog dazu: eqnarray* fracpartial^ Psipartial x^ & -k^ Psi fracpartial Psipartial t & -iomega Psi eqnarray* Eingesetzt in die Gleichung erhalten wir: frachbar^k^mPsi + VPsi hbaromegaPsi. Das ist eine Lösung wenn hbaromega hbar^k^/m + V und dies entspricht der Energieerhaltung: E fracp^m + V wobei E hbar omega und p hbar k ist. enumerate
Contained in these collections
| Title | Creator | Matched on |
|---|---|---|
| Röntgenquant | cm | tags |
| Falsche Compton-Streuung | cm | tags |
| Vermischtes zur QM II | cm | tags |
| Kasten-Potential | cm | tags |
| Planck-Einheiten | cm | tags |
Similar exercises (18)
| Title | Creator | Matched on |
|---|---|---|
| Röntgenquant | cm | tags |
| Falsche Compton-Streuung | cm | tags |
| Vermischtes zur QM II | cm | tags |
| Kasten-Potential | cm | tags |
| Planck-Einheiten | cm | tags |
| Verschobenes Kastenpotential | cm | tags |
| Photoeffekt in Worten | cm | tags |
| Bohrsches Atommodell | cm | tags |
| Compton Streuung | cm | tags |
| Bohrsches Postulat | cm | tags |
| Spektren im Vergleich | cm | tags |
| Atom im Schwerpunkt | cm | tags |
| Herleitung der Schrödinger-Gleichung | cm | tags |
| Wellen oder Teilchen | cm | tags |
| Atome sehen | cm | tags |
| Vermischtes zur QM I | cm | tags |
| SRT+QP für Anfänger | cm | tags |
| Vakuumphotozelle | cm | tags |

