Strecke in Figur berechnen
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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Video
\(\LaTeX\)
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Exercise:
textHalbkreis Rightarrow textQuadrat Rightarrow textKreis; berechne hspacemm x overlineAM center tikzpicture draw halbkreisradius arcstart angle angle radius halbkreisradius cm; draw -halbkreisradius -- halbkreisradius; draw -resultr rectangleresultr*resultr; draw resultr circleradiusresultr cm; fill resultr circleradius. pt; draw resultr*resultr -- ; node at resultr/resultr right small x; node at -.-. small M; node at .*resultr.*resultr leftsmall A; draw -- -.; draw halbkreisradius -- halbkreisradius-.; draw -. -- halbkreisradius/-. -.; draw halbkreisradius/+. -. -- halbkreisradius -.; node at halbkreisradius/-. small MB; node at halbkreisradius -. rightsmall B; fillyellow -- resultr -- resultr*resultr; tikzpicture center
Solution:
Im gelben Dreieck können wir den Radius des Kreises und den Winkel alpha berechnen. Der Radius des Kreises ist genau die Hälfte einer Quadratlänge. Hier eine Skizze: pgfmathsetmacrovalphaasinsqrtresultvonrr/MB vspacemm tikzpicture fillyellow -- resultr -- resultr*resultr; node at resultr/ below r; node at resultr/. resultr below left ; node at resultr resultr below right r; node at resultr/. resultr/. below alpha; tikzpicture vspacemm overlineMB vspacemm Nun können wir mit dem Pythagoras den Radius berechnen da das gelbe Dreieck rechtwinklig ist: r^ + r^ & MB^ r^ + r^ & resultMB r^ & resultMB r^ & numresultvonrr r & sqrtnumresultvonrr Mit den trigonometrischen Funktionen wird der Winkel alpha folgermassen berechnet: sinalpha & fractextGegenkathetetextHypotenuse sin alpha & fracrMB & arcsinfracsqrtnumresultvonrrMB alpha & numvalpha^circ Die Strecke overlineAM kann nun berechnet werden. Hier eine Skizze dazu: vspacemm tikzpicture draw halbkreisradius arcstart angle angle radius halbkreisradius cm; draw -halbkreisradius -- halbkreisradius; draw -resultr rectangleresultr*resultr; draw resultr circleradiusresultr cm; fill resultr circleradius. pt; draw resultr*resultr -- ; node at resultr/resultr right small x; node at -.-. small M; node at .*resultr.*resultr leftsmall A; draw -- -.; draw halbkreisradius -- halbkreisradius-.; draw -. -- halbkreisradius/-. -.; draw halbkreisradius/+. -. -- halbkreisradius -.; node at halbkreisradius/-. small MB; node at halbkreisradius -. rightsmall B; fillgreen -- resultr -- resultr/.resultr*.; tikzpicture hspacemm tikzpicture fillgreen -- resultr -- resultr/.resultr*.; node at resultr/. resultr below right x; node at resultr/. below left r; node at resultr/resultr/. above r; node at resultr/resultr/. above alpha; tikzpicture Wenn wir das grüne Dreieck halbieren haben wir einen rechten Winkel und können mit den trigonometrischen Funktionen rechnen: tikzpicture fillgreen -- resultr -- resultr/.resultr*.; node at resultr/. resultr below right x; node at resultr/. below left r; node at resultr/resultr/. above r; node at resultr/resultr/. above alpha; drawthick resultr/. resultr/. -- resultr; tikzpicture sinalpha & fractextGegenkathetetextHypotenuse cos alpha & fracx/r & fracxr x & rcos alpha pgfmathsetmacroresultx*sqrtresultvonrr*cosvalpha Somit können wir r und alpha einsetzen und das ergibt: x & numresultx
textHalbkreis Rightarrow textQuadrat Rightarrow textKreis; berechne hspacemm x overlineAM center tikzpicture draw halbkreisradius arcstart angle angle radius halbkreisradius cm; draw -halbkreisradius -- halbkreisradius; draw -resultr rectangleresultr*resultr; draw resultr circleradiusresultr cm; fill resultr circleradius. pt; draw resultr*resultr -- ; node at resultr/resultr right small x; node at -.-. small M; node at .*resultr.*resultr leftsmall A; draw -- -.; draw halbkreisradius -- halbkreisradius-.; draw -. -- halbkreisradius/-. -.; draw halbkreisradius/+. -. -- halbkreisradius -.; node at halbkreisradius/-. small MB; node at halbkreisradius -. rightsmall B; fillyellow -- resultr -- resultr*resultr; tikzpicture center
Solution:
Im gelben Dreieck können wir den Radius des Kreises und den Winkel alpha berechnen. Der Radius des Kreises ist genau die Hälfte einer Quadratlänge. Hier eine Skizze: pgfmathsetmacrovalphaasinsqrtresultvonrr/MB vspacemm tikzpicture fillyellow -- resultr -- resultr*resultr; node at resultr/ below r; node at resultr/. resultr below left ; node at resultr resultr below right r; node at resultr/. resultr/. below alpha; tikzpicture vspacemm overlineMB vspacemm Nun können wir mit dem Pythagoras den Radius berechnen da das gelbe Dreieck rechtwinklig ist: r^ + r^ & MB^ r^ + r^ & resultMB r^ & resultMB r^ & numresultvonrr r & sqrtnumresultvonrr Mit den trigonometrischen Funktionen wird der Winkel alpha folgermassen berechnet: sinalpha & fractextGegenkathetetextHypotenuse sin alpha & fracrMB & arcsinfracsqrtnumresultvonrrMB alpha & numvalpha^circ Die Strecke overlineAM kann nun berechnet werden. Hier eine Skizze dazu: vspacemm tikzpicture draw halbkreisradius arcstart angle angle radius halbkreisradius cm; draw -halbkreisradius -- halbkreisradius; draw -resultr rectangleresultr*resultr; draw resultr circleradiusresultr cm; fill resultr circleradius. pt; draw resultr*resultr -- ; node at resultr/resultr right small x; node at -.-. small M; node at .*resultr.*resultr leftsmall A; draw -- -.; draw halbkreisradius -- halbkreisradius-.; draw -. -- halbkreisradius/-. -.; draw halbkreisradius/+. -. -- halbkreisradius -.; node at halbkreisradius/-. small MB; node at halbkreisradius -. rightsmall B; fillgreen -- resultr -- resultr/.resultr*.; tikzpicture hspacemm tikzpicture fillgreen -- resultr -- resultr/.resultr*.; node at resultr/. resultr below right x; node at resultr/. below left r; node at resultr/resultr/. above r; node at resultr/resultr/. above alpha; tikzpicture Wenn wir das grüne Dreieck halbieren haben wir einen rechten Winkel und können mit den trigonometrischen Funktionen rechnen: tikzpicture fillgreen -- resultr -- resultr/.resultr*.; node at resultr/. resultr below right x; node at resultr/. below left r; node at resultr/resultr/. above r; node at resultr/resultr/. above alpha; drawthick resultr/. resultr/. -- resultr; tikzpicture sinalpha & fractextGegenkathetetextHypotenuse cos alpha & fracx/r & fracxr x & rcos alpha pgfmathsetmacroresultx*sqrtresultvonrr*cosvalpha Somit können wir r und alpha einsetzen und das ergibt: x & numresultx
Meta Information
Exercise:
textHalbkreis Rightarrow textQuadrat Rightarrow textKreis; berechne hspacemm x overlineAM center tikzpicture draw halbkreisradius arcstart angle angle radius halbkreisradius cm; draw -halbkreisradius -- halbkreisradius; draw -resultr rectangleresultr*resultr; draw resultr circleradiusresultr cm; fill resultr circleradius. pt; draw resultr*resultr -- ; node at resultr/resultr right small x; node at -.-. small M; node at .*resultr.*resultr leftsmall A; draw -- -.; draw halbkreisradius -- halbkreisradius-.; draw -. -- halbkreisradius/-. -.; draw halbkreisradius/+. -. -- halbkreisradius -.; node at halbkreisradius/-. small MB; node at halbkreisradius -. rightsmall B; fillyellow -- resultr -- resultr*resultr; tikzpicture center
Solution:
Im gelben Dreieck können wir den Radius des Kreises und den Winkel alpha berechnen. Der Radius des Kreises ist genau die Hälfte einer Quadratlänge. Hier eine Skizze: pgfmathsetmacrovalphaasinsqrtresultvonrr/MB vspacemm tikzpicture fillyellow -- resultr -- resultr*resultr; node at resultr/ below r; node at resultr/. resultr below left ; node at resultr resultr below right r; node at resultr/. resultr/. below alpha; tikzpicture vspacemm overlineMB vspacemm Nun können wir mit dem Pythagoras den Radius berechnen da das gelbe Dreieck rechtwinklig ist: r^ + r^ & MB^ r^ + r^ & resultMB r^ & resultMB r^ & numresultvonrr r & sqrtnumresultvonrr Mit den trigonometrischen Funktionen wird der Winkel alpha folgermassen berechnet: sinalpha & fractextGegenkathetetextHypotenuse sin alpha & fracrMB & arcsinfracsqrtnumresultvonrrMB alpha & numvalpha^circ Die Strecke overlineAM kann nun berechnet werden. Hier eine Skizze dazu: vspacemm tikzpicture draw halbkreisradius arcstart angle angle radius halbkreisradius cm; draw -halbkreisradius -- halbkreisradius; draw -resultr rectangleresultr*resultr; draw resultr circleradiusresultr cm; fill resultr circleradius. pt; draw resultr*resultr -- ; node at resultr/resultr right small x; node at -.-. small M; node at .*resultr.*resultr leftsmall A; draw -- -.; draw halbkreisradius -- halbkreisradius-.; draw -. -- halbkreisradius/-. -.; draw halbkreisradius/+. -. -- halbkreisradius -.; node at halbkreisradius/-. small MB; node at halbkreisradius -. rightsmall B; fillgreen -- resultr -- resultr/.resultr*.; tikzpicture hspacemm tikzpicture fillgreen -- resultr -- resultr/.resultr*.; node at resultr/. resultr below right x; node at resultr/. below left r; node at resultr/resultr/. above r; node at resultr/resultr/. above alpha; tikzpicture Wenn wir das grüne Dreieck halbieren haben wir einen rechten Winkel und können mit den trigonometrischen Funktionen rechnen: tikzpicture fillgreen -- resultr -- resultr/.resultr*.; node at resultr/. resultr below right x; node at resultr/. below left r; node at resultr/resultr/. above r; node at resultr/resultr/. above alpha; drawthick resultr/. resultr/. -- resultr; tikzpicture sinalpha & fractextGegenkathetetextHypotenuse cos alpha & fracx/r & fracxr x & rcos alpha pgfmathsetmacroresultx*sqrtresultvonrr*cosvalpha Somit können wir r und alpha einsetzen und das ergibt: x & numresultx
textHalbkreis Rightarrow textQuadrat Rightarrow textKreis; berechne hspacemm x overlineAM center tikzpicture draw halbkreisradius arcstart angle angle radius halbkreisradius cm; draw -halbkreisradius -- halbkreisradius; draw -resultr rectangleresultr*resultr; draw resultr circleradiusresultr cm; fill resultr circleradius. pt; draw resultr*resultr -- ; node at resultr/resultr right small x; node at -.-. small M; node at .*resultr.*resultr leftsmall A; draw -- -.; draw halbkreisradius -- halbkreisradius-.; draw -. -- halbkreisradius/-. -.; draw halbkreisradius/+. -. -- halbkreisradius -.; node at halbkreisradius/-. small MB; node at halbkreisradius -. rightsmall B; fillyellow -- resultr -- resultr*resultr; tikzpicture center
Solution:
Im gelben Dreieck können wir den Radius des Kreises und den Winkel alpha berechnen. Der Radius des Kreises ist genau die Hälfte einer Quadratlänge. Hier eine Skizze: pgfmathsetmacrovalphaasinsqrtresultvonrr/MB vspacemm tikzpicture fillyellow -- resultr -- resultr*resultr; node at resultr/ below r; node at resultr/. resultr below left ; node at resultr resultr below right r; node at resultr/. resultr/. below alpha; tikzpicture vspacemm overlineMB vspacemm Nun können wir mit dem Pythagoras den Radius berechnen da das gelbe Dreieck rechtwinklig ist: r^ + r^ & MB^ r^ + r^ & resultMB r^ & resultMB r^ & numresultvonrr r & sqrtnumresultvonrr Mit den trigonometrischen Funktionen wird der Winkel alpha folgermassen berechnet: sinalpha & fractextGegenkathetetextHypotenuse sin alpha & fracrMB & arcsinfracsqrtnumresultvonrrMB alpha & numvalpha^circ Die Strecke overlineAM kann nun berechnet werden. Hier eine Skizze dazu: vspacemm tikzpicture draw halbkreisradius arcstart angle angle radius halbkreisradius cm; draw -halbkreisradius -- halbkreisradius; draw -resultr rectangleresultr*resultr; draw resultr circleradiusresultr cm; fill resultr circleradius. pt; draw resultr*resultr -- ; node at resultr/resultr right small x; node at -.-. small M; node at .*resultr.*resultr leftsmall A; draw -- -.; draw halbkreisradius -- halbkreisradius-.; draw -. -- halbkreisradius/-. -.; draw halbkreisradius/+. -. -- halbkreisradius -.; node at halbkreisradius/-. small MB; node at halbkreisradius -. rightsmall B; fillgreen -- resultr -- resultr/.resultr*.; tikzpicture hspacemm tikzpicture fillgreen -- resultr -- resultr/.resultr*.; node at resultr/. resultr below right x; node at resultr/. below left r; node at resultr/resultr/. above r; node at resultr/resultr/. above alpha; tikzpicture Wenn wir das grüne Dreieck halbieren haben wir einen rechten Winkel und können mit den trigonometrischen Funktionen rechnen: tikzpicture fillgreen -- resultr -- resultr/.resultr*.; node at resultr/. resultr below right x; node at resultr/. below left r; node at resultr/resultr/. above r; node at resultr/resultr/. above alpha; drawthick resultr/. resultr/. -- resultr; tikzpicture sinalpha & fractextGegenkathetetextHypotenuse cos alpha & fracx/r & fracxr x & rcos alpha pgfmathsetmacroresultx*sqrtresultvonrr*cosvalpha Somit können wir r und alpha einsetzen und das ergibt: x & numresultx
Contained in these collections
| Title | Creator | Matched on |
|---|---|---|
| Winkel in geometrischer Figur | uz | tags |
| Entfernung von Punkten | uz | tags |
| Strecke in Figur | uz | tags |
| Strecke | uz | tags |
| Winkel in Dreieck | uz | tags |
Similar exercises (10)
| Title | Creator | Matched on |
|---|---|---|
| Winkel in geometrischer Figur | uz | tags |
| Entfernung von Punkten | uz | tags |
| Strecke in Figur | uz | tags |
| Strecke | uz | tags |
| Winkel in Dreieck | uz | tags |
| Gleichschenkliges Dreieck | uz | tags |
| Winkel im Kreis | uz | tags |
| Fläche | uz | tags |
| Flächeninhalt | uz | tags |
| Flächeninhalt Trapez | uz | tags |

