Länge von eckiger Spirale
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
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Exercise:
Drei Geraden schneiden sich im Punkt S unter gleich grossen Winkeln. Vom Punkt der auf einer dieser Geraden liegt und acm von S entfernt ist fällt man das Lot auf die Gerade links von P. Vom Fusspunkt des Lotes fällt man das nächste Lot auf die Gerade links davon usw. Wie lang wird die so entstandene Spirale?
Solution:
center tikzpicturescale . shift - coordinate S at ; drawblack thick S -- ; drawblack thick S -- .; drawblack thick S -- -.; drawblack thick S -- -; drawblack thick S -- --.; drawblack thick S -- -.; drawblue thick . -- -.. nodemidway above a_; drawblue thick -.. -- -. nodemidway left a_; drawblue thick -. -- -.-. nodemidway below a_; drawblue thick -.-. -- .-. nodemidway below a_; drawgreen thick . -- S nodemidway right text black a textcm S_; drawgreen thick -.. -- S nodemidway right text black S_; drawgreen thick -. -- S nodemidway above text black S_; drawgreen thick -.-. -- S nodemidway left text black S_; filldrawcolorred fillred!!white S--S+. arc ::.--cycle; nodeblack at . ^circ; tikzpicture center Um die Strecke a_ zu berechnen verwen wir den Sinus von ^circ. * a_ S_ sin^circ S_ fracsqrt * Um die Strecke S_ zu berechnen verwen wir den Kosinus von ^circ * S_ S_ cos^circ S_ frac * Daraus kann man schliessen dass S_n so berechnet werden kann: * S_n S_ cos^circ^n S_ leftfracright^n * Daher wird a_n folgermassen berechnet: * a_n S_n fracsqrt S_ leftfracright^n fracsqrt * Mit a_n kann man nun die Länge der Spirale berechnen: x ^infty_i left S_ leftfracright^i fracsqrtright S_ fracsqrt ^infty_ileftfracright^i Weil die Summe gegen konvergiert erhalten wir als Finales ergebniss: pgfmathsetmacroxa * sqrt/ * x S_ fracsqrt S_ sqrt x textcm
Drei Geraden schneiden sich im Punkt S unter gleich grossen Winkeln. Vom Punkt der auf einer dieser Geraden liegt und acm von S entfernt ist fällt man das Lot auf die Gerade links von P. Vom Fusspunkt des Lotes fällt man das nächste Lot auf die Gerade links davon usw. Wie lang wird die so entstandene Spirale?
Solution:
center tikzpicturescale . shift - coordinate S at ; drawblack thick S -- ; drawblack thick S -- .; drawblack thick S -- -.; drawblack thick S -- -; drawblack thick S -- --.; drawblack thick S -- -.; drawblue thick . -- -.. nodemidway above a_; drawblue thick -.. -- -. nodemidway left a_; drawblue thick -. -- -.-. nodemidway below a_; drawblue thick -.-. -- .-. nodemidway below a_; drawgreen thick . -- S nodemidway right text black a textcm S_; drawgreen thick -.. -- S nodemidway right text black S_; drawgreen thick -. -- S nodemidway above text black S_; drawgreen thick -.-. -- S nodemidway left text black S_; filldrawcolorred fillred!!white S--S+. arc ::.--cycle; nodeblack at . ^circ; tikzpicture center Um die Strecke a_ zu berechnen verwen wir den Sinus von ^circ. * a_ S_ sin^circ S_ fracsqrt * Um die Strecke S_ zu berechnen verwen wir den Kosinus von ^circ * S_ S_ cos^circ S_ frac * Daraus kann man schliessen dass S_n so berechnet werden kann: * S_n S_ cos^circ^n S_ leftfracright^n * Daher wird a_n folgermassen berechnet: * a_n S_n fracsqrt S_ leftfracright^n fracsqrt * Mit a_n kann man nun die Länge der Spirale berechnen: x ^infty_i left S_ leftfracright^i fracsqrtright S_ fracsqrt ^infty_ileftfracright^i Weil die Summe gegen konvergiert erhalten wir als Finales ergebniss: pgfmathsetmacroxa * sqrt/ * x S_ fracsqrt S_ sqrt x textcm
Meta Information
Exercise:
Drei Geraden schneiden sich im Punkt S unter gleich grossen Winkeln. Vom Punkt der auf einer dieser Geraden liegt und acm von S entfernt ist fällt man das Lot auf die Gerade links von P. Vom Fusspunkt des Lotes fällt man das nächste Lot auf die Gerade links davon usw. Wie lang wird die so entstandene Spirale?
Solution:
center tikzpicturescale . shift - coordinate S at ; drawblack thick S -- ; drawblack thick S -- .; drawblack thick S -- -.; drawblack thick S -- -; drawblack thick S -- --.; drawblack thick S -- -.; drawblue thick . -- -.. nodemidway above a_; drawblue thick -.. -- -. nodemidway left a_; drawblue thick -. -- -.-. nodemidway below a_; drawblue thick -.-. -- .-. nodemidway below a_; drawgreen thick . -- S nodemidway right text black a textcm S_; drawgreen thick -.. -- S nodemidway right text black S_; drawgreen thick -. -- S nodemidway above text black S_; drawgreen thick -.-. -- S nodemidway left text black S_; filldrawcolorred fillred!!white S--S+. arc ::.--cycle; nodeblack at . ^circ; tikzpicture center Um die Strecke a_ zu berechnen verwen wir den Sinus von ^circ. * a_ S_ sin^circ S_ fracsqrt * Um die Strecke S_ zu berechnen verwen wir den Kosinus von ^circ * S_ S_ cos^circ S_ frac * Daraus kann man schliessen dass S_n so berechnet werden kann: * S_n S_ cos^circ^n S_ leftfracright^n * Daher wird a_n folgermassen berechnet: * a_n S_n fracsqrt S_ leftfracright^n fracsqrt * Mit a_n kann man nun die Länge der Spirale berechnen: x ^infty_i left S_ leftfracright^i fracsqrtright S_ fracsqrt ^infty_ileftfracright^i Weil die Summe gegen konvergiert erhalten wir als Finales ergebniss: pgfmathsetmacroxa * sqrt/ * x S_ fracsqrt S_ sqrt x textcm
Drei Geraden schneiden sich im Punkt S unter gleich grossen Winkeln. Vom Punkt der auf einer dieser Geraden liegt und acm von S entfernt ist fällt man das Lot auf die Gerade links von P. Vom Fusspunkt des Lotes fällt man das nächste Lot auf die Gerade links davon usw. Wie lang wird die so entstandene Spirale?
Solution:
center tikzpicturescale . shift - coordinate S at ; drawblack thick S -- ; drawblack thick S -- .; drawblack thick S -- -.; drawblack thick S -- -; drawblack thick S -- --.; drawblack thick S -- -.; drawblue thick . -- -.. nodemidway above a_; drawblue thick -.. -- -. nodemidway left a_; drawblue thick -. -- -.-. nodemidway below a_; drawblue thick -.-. -- .-. nodemidway below a_; drawgreen thick . -- S nodemidway right text black a textcm S_; drawgreen thick -.. -- S nodemidway right text black S_; drawgreen thick -. -- S nodemidway above text black S_; drawgreen thick -.-. -- S nodemidway left text black S_; filldrawcolorred fillred!!white S--S+. arc ::.--cycle; nodeblack at . ^circ; tikzpicture center Um die Strecke a_ zu berechnen verwen wir den Sinus von ^circ. * a_ S_ sin^circ S_ fracsqrt * Um die Strecke S_ zu berechnen verwen wir den Kosinus von ^circ * S_ S_ cos^circ S_ frac * Daraus kann man schliessen dass S_n so berechnet werden kann: * S_n S_ cos^circ^n S_ leftfracright^n * Daher wird a_n folgermassen berechnet: * a_n S_n fracsqrt S_ leftfracright^n fracsqrt * Mit a_n kann man nun die Länge der Spirale berechnen: x ^infty_i left S_ leftfracright^i fracsqrtright S_ fracsqrt ^infty_ileftfracright^i Weil die Summe gegen konvergiert erhalten wir als Finales ergebniss: pgfmathsetmacroxa * sqrt/ * x S_ fracsqrt S_ sqrt x textcm
Contained in these collections
| Title | Creator | Matched on |
|---|---|---|
| Quadrat und Kreis | uz | tags |
| Länge von Zickzack-Bewegung | uz | tags |
| Länge einer eckigen Spirale | uz | tagstitle |
| Unendlicher Streckenzug | uz | tags |
| Winkel des Parallelogramms | uz | tags |
Similar exercises (12)
| Title | Creator | Matched on |
|---|---|---|
| Quadrat und Kreis | uz | tags |
| Länge von Zickzack-Bewegung | uz | tags |
| Länge einer eckigen Spirale | uz | tagstitle |
| Unendlicher Streckenzug | uz | tags |
| Winkel des Parallelogramms | uz | tags |
| Länge von Streckenzug | uz | tags |
| Dreiecksfläche | uz | tags |
| Blatt zerschneiden und stapeln | uz | tags |
| Fläche von spiralförmiger Figur | uz | tags |
| Streckenlänge | uz | tags |
| Grenzwert von Folge | uz | tags |
| Zickzackweg | uz | tags |

