Länge von Streckenzug
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
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Exercise:
Im Quadrat mit der Seitenlänge s s wird von A ausgeh ein Streckenzug mit unlich vielen Strecken eingezeichnet. Wie lange ist dieser Streckenzug Linie in Blau und Gelb? center tikzpicturescale draw -- s -- ss -- s--cycle; draw cyan line widthmm -- ss; draw yellow line widthmmss -- halfs; draw cyan line widthmmhalfs--shalfs; draw yellow line widthmmshalfs-- basess; draw cyan line widthmmbasess-- shalfss; draw yellow line widthmmshalfss-- basesss; draw cyan line widthmmbasesss-- shalfsss; draw yellow line widthmmshalfsss-- basessss; draw cyan line widthmmbasessss-- shalfssss; draw shalfssss-- basesssss -- s halfsssss; draw -- ss; draw ss -- halfs; draw halfs--shalfs; draw shalfs-- basess; draw basess-- shalfss; draw shalfss-- basesss; draw basesss-- s halfsss; draw shalfsss-- basessss; draw basessss-- shalfssss; coordinate A at ; node at -. A; node at halfs-. fracs; node at basess-. fracs; node at basesss-. fracs; node at -.halfs s; node at snodehalfs fracs; node at snodehalfss fracs; node at snodehalfsss fracs; tikzpicture center
Solution:
Zuerst berechnen wir gegen welche Zahl die textcolorcyanblaue Strecke konvergiert. Mit dem Satz des Pythagoras: s_^ s^ + s^ s^ s_^ fracs^ + fracs^ fracs^ s_^ fracs^ + fracs^ fracs^ vdots notag Daraus schliesst sich: s_ sqrt s s_ sqrt fracs s_ sqrt fracs vdots notag textcolorcyans s_ + s_+ s_ + dots textcolorcyans sqrt s +sqrt fracs +sqrt fracs + dots textcolorcyans sqrt textcolorreds +fracs + fracs + fracs + dots &textDer textcolorredrote Teil konvergiert gegen skonvert notag textcolorcyans textcolorcyan sqrt skonvert Als nächstes berechnen wir noch gegen welche Zahl die textcoloryellowgelbe Strecke konvergiert. Mit dem Satz des Pythagoras: s_^ s^ + fracs^ frac s_^ frac^ + frac^ frac s_^ frac^ + frac^ frac vdots notag Daraus schliesst sich: s_ fracsqrt s_ fracsqrt s_ fracsqrt vdots notag textcoloryellows s_ + s_+ s_ + dots textcoloryellows fracsqrt +fracsqrt +fracsqrt + dots textcoloryellows fracsqrt textcolorred+frac+frac+ dots &textDer textcolorredrote Teil konvergiert gegen notag textcoloryellows textcoloryellowsqrt Die Länge des Streckenszugs ist also: s textcolorcyans + textcoloryellows s textcolorcyan sqrt skonvert +textcoloryellowsqrt s &approx fpevalroundsqrt*skonvert + sqrt
Im Quadrat mit der Seitenlänge s s wird von A ausgeh ein Streckenzug mit unlich vielen Strecken eingezeichnet. Wie lange ist dieser Streckenzug Linie in Blau und Gelb? center tikzpicturescale draw -- s -- ss -- s--cycle; draw cyan line widthmm -- ss; draw yellow line widthmmss -- halfs; draw cyan line widthmmhalfs--shalfs; draw yellow line widthmmshalfs-- basess; draw cyan line widthmmbasess-- shalfss; draw yellow line widthmmshalfss-- basesss; draw cyan line widthmmbasesss-- shalfsss; draw yellow line widthmmshalfsss-- basessss; draw cyan line widthmmbasessss-- shalfssss; draw shalfssss-- basesssss -- s halfsssss; draw -- ss; draw ss -- halfs; draw halfs--shalfs; draw shalfs-- basess; draw basess-- shalfss; draw shalfss-- basesss; draw basesss-- s halfsss; draw shalfsss-- basessss; draw basessss-- shalfssss; coordinate A at ; node at -. A; node at halfs-. fracs; node at basess-. fracs; node at basesss-. fracs; node at -.halfs s; node at snodehalfs fracs; node at snodehalfss fracs; node at snodehalfsss fracs; tikzpicture center
Solution:
Zuerst berechnen wir gegen welche Zahl die textcolorcyanblaue Strecke konvergiert. Mit dem Satz des Pythagoras: s_^ s^ + s^ s^ s_^ fracs^ + fracs^ fracs^ s_^ fracs^ + fracs^ fracs^ vdots notag Daraus schliesst sich: s_ sqrt s s_ sqrt fracs s_ sqrt fracs vdots notag textcolorcyans s_ + s_+ s_ + dots textcolorcyans sqrt s +sqrt fracs +sqrt fracs + dots textcolorcyans sqrt textcolorreds +fracs + fracs + fracs + dots &textDer textcolorredrote Teil konvergiert gegen skonvert notag textcolorcyans textcolorcyan sqrt skonvert Als nächstes berechnen wir noch gegen welche Zahl die textcoloryellowgelbe Strecke konvergiert. Mit dem Satz des Pythagoras: s_^ s^ + fracs^ frac s_^ frac^ + frac^ frac s_^ frac^ + frac^ frac vdots notag Daraus schliesst sich: s_ fracsqrt s_ fracsqrt s_ fracsqrt vdots notag textcoloryellows s_ + s_+ s_ + dots textcoloryellows fracsqrt +fracsqrt +fracsqrt + dots textcoloryellows fracsqrt textcolorred+frac+frac+ dots &textDer textcolorredrote Teil konvergiert gegen notag textcoloryellows textcoloryellowsqrt Die Länge des Streckenszugs ist also: s textcolorcyans + textcoloryellows s textcolorcyan sqrt skonvert +textcoloryellowsqrt s &approx fpevalroundsqrt*skonvert + sqrt
Meta Information
Exercise:
Im Quadrat mit der Seitenlänge s s wird von A ausgeh ein Streckenzug mit unlich vielen Strecken eingezeichnet. Wie lange ist dieser Streckenzug Linie in Blau und Gelb? center tikzpicturescale draw -- s -- ss -- s--cycle; draw cyan line widthmm -- ss; draw yellow line widthmmss -- halfs; draw cyan line widthmmhalfs--shalfs; draw yellow line widthmmshalfs-- basess; draw cyan line widthmmbasess-- shalfss; draw yellow line widthmmshalfss-- basesss; draw cyan line widthmmbasesss-- shalfsss; draw yellow line widthmmshalfsss-- basessss; draw cyan line widthmmbasessss-- shalfssss; draw shalfssss-- basesssss -- s halfsssss; draw -- ss; draw ss -- halfs; draw halfs--shalfs; draw shalfs-- basess; draw basess-- shalfss; draw shalfss-- basesss; draw basesss-- s halfsss; draw shalfsss-- basessss; draw basessss-- shalfssss; coordinate A at ; node at -. A; node at halfs-. fracs; node at basess-. fracs; node at basesss-. fracs; node at -.halfs s; node at snodehalfs fracs; node at snodehalfss fracs; node at snodehalfsss fracs; tikzpicture center
Solution:
Zuerst berechnen wir gegen welche Zahl die textcolorcyanblaue Strecke konvergiert. Mit dem Satz des Pythagoras: s_^ s^ + s^ s^ s_^ fracs^ + fracs^ fracs^ s_^ fracs^ + fracs^ fracs^ vdots notag Daraus schliesst sich: s_ sqrt s s_ sqrt fracs s_ sqrt fracs vdots notag textcolorcyans s_ + s_+ s_ + dots textcolorcyans sqrt s +sqrt fracs +sqrt fracs + dots textcolorcyans sqrt textcolorreds +fracs + fracs + fracs + dots &textDer textcolorredrote Teil konvergiert gegen skonvert notag textcolorcyans textcolorcyan sqrt skonvert Als nächstes berechnen wir noch gegen welche Zahl die textcoloryellowgelbe Strecke konvergiert. Mit dem Satz des Pythagoras: s_^ s^ + fracs^ frac s_^ frac^ + frac^ frac s_^ frac^ + frac^ frac vdots notag Daraus schliesst sich: s_ fracsqrt s_ fracsqrt s_ fracsqrt vdots notag textcoloryellows s_ + s_+ s_ + dots textcoloryellows fracsqrt +fracsqrt +fracsqrt + dots textcoloryellows fracsqrt textcolorred+frac+frac+ dots &textDer textcolorredrote Teil konvergiert gegen notag textcoloryellows textcoloryellowsqrt Die Länge des Streckenszugs ist also: s textcolorcyans + textcoloryellows s textcolorcyan sqrt skonvert +textcoloryellowsqrt s &approx fpevalroundsqrt*skonvert + sqrt
Im Quadrat mit der Seitenlänge s s wird von A ausgeh ein Streckenzug mit unlich vielen Strecken eingezeichnet. Wie lange ist dieser Streckenzug Linie in Blau und Gelb? center tikzpicturescale draw -- s -- ss -- s--cycle; draw cyan line widthmm -- ss; draw yellow line widthmmss -- halfs; draw cyan line widthmmhalfs--shalfs; draw yellow line widthmmshalfs-- basess; draw cyan line widthmmbasess-- shalfss; draw yellow line widthmmshalfss-- basesss; draw cyan line widthmmbasesss-- shalfsss; draw yellow line widthmmshalfsss-- basessss; draw cyan line widthmmbasessss-- shalfssss; draw shalfssss-- basesssss -- s halfsssss; draw -- ss; draw ss -- halfs; draw halfs--shalfs; draw shalfs-- basess; draw basess-- shalfss; draw shalfss-- basesss; draw basesss-- s halfsss; draw shalfsss-- basessss; draw basessss-- shalfssss; coordinate A at ; node at -. A; node at halfs-. fracs; node at basess-. fracs; node at basesss-. fracs; node at -.halfs s; node at snodehalfs fracs; node at snodehalfss fracs; node at snodehalfsss fracs; tikzpicture center
Solution:
Zuerst berechnen wir gegen welche Zahl die textcolorcyanblaue Strecke konvergiert. Mit dem Satz des Pythagoras: s_^ s^ + s^ s^ s_^ fracs^ + fracs^ fracs^ s_^ fracs^ + fracs^ fracs^ vdots notag Daraus schliesst sich: s_ sqrt s s_ sqrt fracs s_ sqrt fracs vdots notag textcolorcyans s_ + s_+ s_ + dots textcolorcyans sqrt s +sqrt fracs +sqrt fracs + dots textcolorcyans sqrt textcolorreds +fracs + fracs + fracs + dots &textDer textcolorredrote Teil konvergiert gegen skonvert notag textcolorcyans textcolorcyan sqrt skonvert Als nächstes berechnen wir noch gegen welche Zahl die textcoloryellowgelbe Strecke konvergiert. Mit dem Satz des Pythagoras: s_^ s^ + fracs^ frac s_^ frac^ + frac^ frac s_^ frac^ + frac^ frac vdots notag Daraus schliesst sich: s_ fracsqrt s_ fracsqrt s_ fracsqrt vdots notag textcoloryellows s_ + s_+ s_ + dots textcoloryellows fracsqrt +fracsqrt +fracsqrt + dots textcoloryellows fracsqrt textcolorred+frac+frac+ dots &textDer textcolorredrote Teil konvergiert gegen notag textcoloryellows textcoloryellowsqrt Die Länge des Streckenszugs ist also: s textcolorcyans + textcoloryellows s textcolorcyan sqrt skonvert +textcoloryellowsqrt s &approx fpevalroundsqrt*skonvert + sqrt
Contained in these collections
| Title | Creator | Matched on |
|---|---|---|
| Quadrat und Kreis | uz | tags |
| Länge von Zickzack-Bewegung | uz | tags |
| Länge einer eckigen Spirale | uz | tags |
| Unendlicher Streckenzug | uz | tags |
| Winkel des Parallelogramms | uz | tags |
Similar exercises (12)
| Title | Creator | Matched on |
|---|---|---|
| Quadrat und Kreis | uz | tags |
| Länge von Zickzack-Bewegung | uz | tags |
| Länge einer eckigen Spirale | uz | tags |
| Unendlicher Streckenzug | uz | tags |
| Winkel des Parallelogramms | uz | tags |
| Länge von eckiger Spirale | uz | tags |
| Dreiecksfläche | uz | tags |
| Blatt zerschneiden und stapeln | uz | tags |
| Fläche von spiralförmiger Figur | uz | tags |
| Streckenlänge | uz | tags |
| Grenzwert von Folge | uz | tags |
| Zickzackweg | uz | tags |

