Exercise
https://texercises.com/exercise/rollende-kugel-1/
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The following quantities appear in the problem: Winkelbeschleunigung \(\alpha\) / Trägheitsmoment \(J, \Theta, I\) / Energie \(E\) / Winkel \(\theta\) / Radius \(r\) / Ortsfaktor \(g\) / Höhe \(h\) / Geschwindigkeit \(v\) / Länge \(\ell\) / Winkelgeschwindigkeit / Kreisfrequenz \(\omega\) / Kraft \(F\) / Drehmoment \(\vec M\) / Masse \(m\) / Beschleunigung \(a\) /
The following formulas must be used to solve the exercise: \(a = r\alpha \quad \) \(v = r \omega \quad \) \(M = J\alpha \quad \) \(\vec M = \vec \ell \times \vec F \quad \) \(\sum E_{\scriptscriptstyle\rm tot} \stackrel{!}{=} \sum E_{\scriptscriptstyle\rm tot}' \quad \) \(E_{\rm \scriptscriptstyle kin} = \dfrac12 mv^2 \quad \) \(F = ma \quad \) \(E_{\rm \scriptscriptstyle pot} = mgh \quad \) \(E = \frac12 J\omega^2 \quad \) \(J_a = J_s + mr^2 \quad \) \(F_\bot = F_G\cdot \cos\alpha \quad \) \(J = \frac25 mr^2 \quad \) \(J = \frac12 mr^2 \quad \)
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Exercise:
Eine Kugel rollt aus der Ruheposition reibungsfrei eine schiefe Ebene vgl. Abb. herunter. Welche Geschwindigkeit hat sie am Ende der Ebene? center tikzpicture % Schiefe Ebene draw thick -- ++ -- *tan -- cycle; % Winkel draw thick . arc :-:. node leftyshift-.mm fns alpha; % Kugel shadedraw shadingballball colorblue!drawnone .*tan+. circle .cm; % Strecke draw -.*tan+. -- node above fns s +..; tikzpicture center

Solution:
Die Energiebilanz lautet: eqnarray* E_pot & E_kin mgh & fracmv^ gssinalpha & fracv^ eqnarray* wobei h ssinalpha ist. Somit erhalten wir: v sqrtgssinalpha.
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Exercise:
Eine Kugel rollt aus der Ruheposition reibungsfrei eine schiefe Ebene vgl. Abb. herunter. Welche Geschwindigkeit hat sie am Ende der Ebene? center tikzpicture % Schiefe Ebene draw thick -- ++ -- *tan -- cycle; % Winkel draw thick . arc :-:. node leftyshift-.mm fns alpha; % Kugel shadedraw shadingballball colorblue!drawnone .*tan+. circle .cm; % Strecke draw -.*tan+. -- node above fns s +..; tikzpicture center

Solution:
Die Energiebilanz lautet: eqnarray* E_pot & E_kin mgh & fracmv^ gssinalpha & fracv^ eqnarray* wobei h ssinalpha ist. Somit erhalten wir: v sqrtgssinalpha.
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Attributes & Decorations
Topic
Tags
energie und impuls, energieerhaltungssatz, mechanik
Difficulty
(1, default)
Points
0 (default)
Language
GER (Deutsch)
Type
Calculative / Quantity
Decoration
Content image

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